Which equation shows the commutative property of addition? Choices: (A)r + s = s + r (B)r = r + 0 (C)0 + r = r (D)r + (s + t) = (r + s) + t

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Which equation shows the commutative property of addition?    Choices: (A)r + s = s + r (B)r = r + 0 (C)0 + r = r (D)r + (s + t) = (r + s) + t

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Define Commutative Property: Identify the definition of the commutative property of addition. The commutative property of addition states that the order in which two numbers are added does not change the sum. In other words, a + b = b + a.Match Definition to Choices: Match the definition to the given choices. The commutative property is represented by the equation where the order of the addends can be switched without changing the sum. We are looking for an equation of the form a + b = b + a.Analyze Each Choice: Analyze each choice to see if it matches the commutative property. (A) r + s = s + r - This matches the commutative property definition. (B) r = r + 0 - This does not show commutativity; it shows the identity property of addition. (C) 0 + r = r - This also shows the identity property of addition, not commutativity. (D) r + (s + t) = (r + s) + t - This shows the associative property of addition, not commutativity.Select Correct Answer: Select the correct answer based on the analysis. The correct answer is (A) r + s = s + r because it is the only choice that demonstrates the commutative property of addition.

Which equation shows the commutative property of addition? $\newline$ Choices: $\newline$ (A) $r + s = s + r$ $\newline$ (B) $r = r + 0$ $\newline$ (C) $0 + r = r$ $\newline$ (D) $r + (s + t) = (r + s) + t$

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Which equation shows the commutative property of addition?\newlineChoices:\newline(A) r+s=s+rr + s = s + rr+s=s+r\newline(B) r=r+0r = r + 0r=r+0\newline(C) 0+r=r0 + r = r0+r=r\newline(D) r+(s+t)=(r+s)+tr + (s + t) = (r + s) + tr+(s+t)=(r+s)+t

Which equation shows the commutative property of addition? $\newline$ Choices: $\newline$ (A) $r + s = s + r$ $\newline$ (B) $r = r + 0$ $\newline$ (C) $0 + r = r$ $\newline$ (D) $r + (s + t) = (r + s) + t$