Which equation shows the associative property of multiplication? Choices: (A)g · (h · j) = (g · h) · j (B)g = g · 1 (C)g · 1 = g (D)0 = g · 0

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Which equation shows the associative property of multiplication?    Choices: (A)g · (h · j) = (g · h) · j (B)g = g · 1 (C)g · 1 = g (D)0 = g · 0

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Property of Multiplication: The associative property of multiplication states that when three or more numbers are multiplied, the way in which they are grouped does not affect the product. In other words, (a · b) · c = a · (b · c). We need to find the equation that represents this property from the given choices.Examine Choice (A): Let's examine choice (A): g · (h · j) = (g · h) · j. This equation shows that the product of g and the product of h and j is the same as the product of g and h and then multiplying the result by j. This is the associative property of multiplication.Choice (B): Choice (B): g = g · 1 does not represent the associative property. It represents the identity property of multiplication, which states that any number multiplied by 1 equals the number itself.Choice (C): Choice (C): g · 1 = g also represents the identity property of multiplication, not the associative property.Choice (D): Choice (D): 0 = g · 0 represents the zero property of multiplication, which states that any number multiplied by 0 equals 0.Conclusion: Based on the examination of all choices, we can conclude that choice (A) correctly represents the associative property of multiplication.

Which equation shows the associative property of multiplication? $\newline$ Choices: $\newline$ (A) $g \cdot (h \cdot j) = (g \cdot h) \cdot j$ $\newline$ (B) $g = g \cdot 1$ $\newline$ (C) $g \cdot 1 = g$ $\newline$ (D) $0 = g \cdot 0$

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Which equation shows the associative property of multiplication?\newlineChoices:\newline(A) g⋅(h⋅j)=(g⋅h)⋅jg \cdot (h \cdot j) = (g \cdot h) \cdot jg⋅(h⋅j)=(g⋅h)⋅j\newline(B) g=g⋅1g = g \cdot 1g=g⋅1\newline(C) g⋅1=gg \cdot 1 = gg⋅1=g\newline(D) 0=g⋅00 = g \cdot 00=g⋅0

Which equation shows the associative property of multiplication? $\newline$ Choices: $\newline$ (A) $g \cdot (h \cdot j) = (g \cdot h) \cdot j$ $\newline$ (B) $g = g \cdot 1$ $\newline$ (C) $g \cdot 1 = g$ $\newline$ (D) $0 = g \cdot 0$