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Which equation has the solution 
x=3 ?

8x-4=-20

6x+7=64

4x-7=5

8x-1=87

Which equation has the solution x=3 x=3 ?\newline8x4=20 8 x-4=-20 \newline6x+7=64 6 x+7=64 \newline4x7=5 4 x-7=5 \newline8x1=87 8 x-1=87

Full solution

Q. Which equation has the solution x=3 x=3 ?\newline8x4=20 8 x-4=-20 \newline6x+7=64 6 x+7=64 \newline4x7=5 4 x-7=5 \newline8x1=87 8 x-1=87
  1. Substitute x=3x=3: Let's start by substituting x=3x=3 into the first equation 8x4=208x-4=-20 and see if it holds true.\newlineCalculation: 8(3)4=244=208(3) - 4 = 24 - 4 = 20\newlineNow, let's compare this result with the right side of the equation.\newline202020 \neq -20
  2. Check first equation: Since the first equation does not hold true for x=3x=3, let's try the second equation 6x+7=646x+7=64.\newlineCalculation: 6(3)+7=18+7=256(3) + 7 = 18 + 7 = 25\newlineNow, let's compare this result with the right side of the equation.\newline256425 \neq 64
  3. Check second equation: The second equation also does not hold true for x=3x=3, so let's try the third equation 4x7=54x-7=5.\newlineCalculation: 4(3)7=127=54(3) - 7 = 12 - 7 = 5\newlineNow, let's compare this result with the right side of the equation.\newline5=55 = 5\newlineThis equation holds true for x=3x=3.
  4. Check third equation: Since we have found an equation that holds true for x=3x=3, there is no need to check the fourth equation. However, for completeness, let's check the fourth equation 8x1=878x-1=87.\newlineCalculation: 8(3)1=241=238(3) - 1 = 24 - 1 = 23\newlineNow, let's compare this result with the right side of the equation.\newline238723 \neq 87

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