Q. Which equation has the same solution as x2+14x+20=8 ?(x−7)2=37(x−7)2=−61(x+7)2=37(x+7)2=−61
Simplify the equation: First, let's simplify the given equation x2+14x+20=8 by moving all terms to one side to set the equation to zero.x2+14x+20−8=0x2+14x+12=0
Factor the quadratic equation: Now, we need to factor the quadratic equationx2+14x+12. (x+2)(x+6)=0
Find solutions for x: Next, we find the solutions for x by setting each factor equal to zero.x+2=0 or x+6=0x=−2 or x=−6
Compare with given options: Now, let's compare the solutions x=−2 and x=−6 with the options given. We need to find which equation has the same solutions.We will start with the first option: (x−7)2=37.Let's solve for x.(x−7)2=37Take the square root of both sides.x−7=±37x=7±37This does not match our solutions of x=−2 or x=−6.
Check first option: Next, we check the second option: (x−7)2=−61. Since the square of a real number cannot be negative, this equation has no real solutions. This does not match our solutions of x=−2 or x=−6.
Check second option: Now, we check the third option: (x+7)2=37. Let's solve for x. (x+7)2=37 Take the square root of both sides. x+7=±37x=−7±37 This does not match our solutions of x=−2 or x=−6.
Check third option: Finally, we check the fourth option: x+7^{2}=−61. Similar to the second option, this equation has no real solutions because the square of a real number cannot be negative. This does not match our solutions of x=−2 or x=−6.
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