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Which equation has the same solution as 
x^(2)+14 x+20=8 ?

(x-7)^(2)=37

(x-7)^(2)=-61

(x+7)^(2)=37

(x+7)^(2)=-61

Which equation has the same solution as x2+14x+20=8 x^{2}+14 x+20=8 ?\newline(x7)2=37 (x-7)^{2}=37 \newline(x7)2=61 (x-7)^{2}=-61 \newline(x+7)2=37 (x+7)^{2}=37 \newline(x+7)2=61 (x+7)^{2}=-61

Full solution

Q. Which equation has the same solution as x2+14x+20=8 x^{2}+14 x+20=8 ?\newline(x7)2=37 (x-7)^{2}=37 \newline(x7)2=61 (x-7)^{2}=-61 \newline(x+7)2=37 (x+7)^{2}=37 \newline(x+7)2=61 (x+7)^{2}=-61
  1. Simplify the equation: First, let's simplify the given equation x2+14x+20=8x^{2}+14x+20=8 by moving all terms to one side to set the equation to zero.\newlinex2+14x+208=0x^{2} + 14x + 20 - 8 = 0\newlinex2+14x+12=0x^{2} + 14x + 12 = 0
  2. Factor the quadratic equation: Now, we need to factor the quadratic equation x2+14x+12x^{2} + 14x + 12. \newline(x+2)(x+6)=0(x + 2)(x + 6) = 0
  3. Find solutions for xx: Next, we find the solutions for xx by setting each factor equal to zero.\newlinex+2=0x + 2 = 0 or x+6=0x + 6 = 0\newlinex=2x = -2 or x=6x = -6
  4. Compare with given options: Now, let's compare the solutions x=2x = -2 and x=6x = -6 with the options given. We need to find which equation has the same solutions.\newlineWe will start with the first option: (x7)2=37(x-7)^{2}=37.\newlineLet's solve for x.\newline(x7)2=37(x - 7)^2 = 37\newlineTake the square root of both sides.\newlinex7=±37x - 7 = \pm\sqrt{37}\newlinex=7±37x = 7 \pm \sqrt{37}\newlineThis does not match our solutions of x=2x = -2 or x=6x = -6.
  5. Check first option: Next, we check the second option: (x7)2=61(x-7)^{2}=-61. Since the square of a real number cannot be negative, this equation has no real solutions. This does not match our solutions of x=2x = -2 or x=6x = -6.
  6. Check second option: Now, we check the third option: (x+7)2=37(x+7)^{2}=37. Let's solve for xx. (x+7)2=37(x + 7)^2 = 37 Take the square root of both sides. x+7=±37x + 7 = \pm\sqrt{37} x=7±37x = -7 \pm \sqrt{37} This does not match our solutions of x=2x = -2 or x=6x = -6.
  7. Check third option: Finally, we check the fourth option: x+7x+7^{22}=61-61. Similar to the second option, this equation has no real solutions because the square of a real number cannot be negative. This does not match our solutions of x=2x = -2 or x=6x = -6.

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