Which equation has both 3 and -3 as possible values of x? Select all that apply. Multi-select Choices: (A)x^2 = 6 (B)x^3 = 6 (C)x^2 = 9 (D)x^3 = 9 (E)x^2 = 27 (F)x^3 = 27

Check Equation (A): Step 1: Check equation (A) x^2 = 6. Plug in x = 3 and x = -3: 3^2 = 9 and (-3)^2 = 9. Both are not equal to 6. Check Equation (B): Step 2: Check equation (B) x^3 = 6. Plug in x = 3 and x = -3: 3^3 = 27 and (-3)^3 = -27. Neither equals 6. Check Equation (C): Step 3: Check equation (C) x^2 = 9. Plug in x = 3 and x = -3: 3^2 = 9 and (-3)^2 = 9. Both equal 9, so this equation works. Check Equation (D): Step 4: Check equation (D) x^3 = 9. Plug in x = 3 and x = -3: 3^3 = 27 and (-3)^3 = -27. Neither equals 9. Check Equation (E): Step 5: Check equation (E) x^2 = 27. Plug in x = 3 and x = -3: 3^2 = 9 and (-3)^2 = 9. Both are not equal to 27. Check Equation (F): Step 6: Check equation (F) x^3 = 27. Plug in x = 3 and x = -3: 3^3 = 27 and (-3)^3 = -27. Only x = 3 equals 27, not -3.

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Which equation has both $3$ and $-3$ as possible values of $x$ ? Select all that apply. $\newline$ Multi-select Choices: $\newline$ (A) $x^2 = 6$ $\newline$ (B) $x^3 = 6$ $\newline$ (C) $x^2 = 9$ $\newline$ (D) $x^3 = 9$ $\newline$ (E) $x^2 = 27$ $\newline$ (F) $x^3 = 27$

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Math Problems

Algebra 2

Simplify rational expressions

Full solution

Q. Which equation has both

3

and

-3

as possible values of

x

? Select all that apply.

\newline

Multi-select Choices:

\newline

(A)

x^2 = 6

\newline

(B)

x^3 = 6

\newline

(C)

x^2 = 9

\newline

(D)

x^3 = 9

\newline

(E)

x^2 = 27

\newline

(F)

x^3 = 27

Check Equation (A): Step $1$ : Check equation (A) $x^2 = 6$ . $\newline$ Plug in $x = 3$ and $x = -3$ : $\newline$ $3^2 = 9$ and $(-3)^2 = 9$ . $\newline$ Both are not equal to $6$ .
Check Equation (B): Step $2$ : Check equation (B) $x^3 = 6$ . $\newline$ Plug in $x = 3$ and $x = -3$ : $\newline$ $3^3 = 27$ and $(-3)^3 = -27$ . $\newline$ Neither equals $6$ .
Check Equation (C): Step $3$ : Check equation (C) $x^2 = 9$ . $\newline$ Plug in $x = 3$ and $x = -3$ : $\newline$ $3^2 = 9$ and $(-3)^2 = 9$ . $\newline$ Both equal $9$ , so this equation works.
Check Equation (D): Step $4$ : Check equation (D) $x^3 = 9$ . $\newline$ Plug in $x = 3$ and $x = -3$ : $\newline$ $3^3 = 27$ and $(-3)^3 = -27$ . $\newline$ Neither equals $9$ .
Check Equation (E): Step $5$ : Check equation (E) $x^2 = 27$ . $\newline$ Plug in $x = 3$ and $x = -3$ : $\newline$ $3^2 = 9$ and $(-3)^2 = 9$ . $\newline$ Both are not equal to $27$ .
Check Equation (F): Step $6$ : Check equation (F) $x^3 = 27$ . $\newline$ Plug in $x = 3$ and $x = -3$ : $\newline$ $3^3 = 27$ and $(-3)^3 = -27$ . $\newline$ Only $x = 3$ equals $27$ , not $-3$ .