Which equation has a constant of proportionality equal to 10 ? Choose 1 answer: A y=(2)/(20)x (B) y=(30)/(3)x (C) y=(12)/(2)x (D) y=(5)/(5)x

Understand Constant of Proportionality: First, we need to understand that the constant of proportionality is the constant (k) in the equation y = kx. We will find the constant of proportionality for each given equation by simplifying the right-hand side of the equation.Option A: Simplify Fraction: For option A, y = (2/20)x, we simplify the fraction 2/20 to get the constant of proportionality. Dividing both the numerator and the denominator by 2, we get 1/10. Therefore, the constant of proportionality for option A is 1/10.Option B: Simplify Fraction: For option B, y = (30/3)x, we simplify the fraction 30/3 to get the constant of proportionality. Dividing both the numerator and the denominator by 3, we get 10. Therefore, the constant of proportionality for option B is 10.Option C: Simplify Fraction: For option C, y = (12/2)x, we simplify the fraction 12/2 to get the constant of proportionality. Dividing both the numerator and the denominator by 2, we get 6. Therefore, the constant of proportionality for option C is 6.Option D: Simplify Fraction: For option D, y = (5/5)x, we simplify the fraction 5/5 to get the constant of proportionality. Dividing both the numerator and the denominator by 5, we get 1. Therefore, the constant of proportionality for option D is 1.

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Which equation has a constant of proportionality equal to 10 ?
Choose 1 answer:
A
y=(2)/(20)x
(B)
y=(30)/(3)x
(C)
y=(12)/(2)x
(D)
y=(5)/(5)x

Which equation has a constant of proportionality equal to $10$ ? $\newline$ Choose $1$ answer: $\newline$ A $y=\frac{2}{20} x$ $\newline$ (B) $y=\frac{30}{3} x$ $\newline$ (C) $y=\frac{12}{2} x$ $\newline$ (D) $y=\frac{5}{5} x$

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Math Problems

Algebra 2

Write joint and combined variation equations II

Full solution

Q. Which equation has a constant of proportionality equal to

10

\newline

Choose

1

answer:

\newline

y=\frac{2}{20} x

\newline

(B)

y=\frac{30}{3} x

\newline

(C)

y=\frac{12}{2} x

\newline

(D)

y=\frac{5}{5} x

Understand Constant of Proportionality: First, we need to understand that the constant of proportionality is the constant $k$ in the equation $y = kx$ . We will find the constant of proportionality for each given equation by simplifying the right-hand side of the equation.
Option A: Simplify Fraction: For option A, $y = \frac{2}{20}x$ , we simplify the fraction $\frac{2}{20}$ to get the constant of proportionality. Dividing both the numerator and the denominator by $2$ , we get $\frac{1}{10}$ . Therefore, the constant of proportionality for option A is $\frac{1}{10}$ .
Option B: Simplify Fraction: For option B, $y = \frac{30}{3}x$ , we simplify the fraction $\frac{30}{3}$ to get the constant of proportionality. Dividing both the numerator and the denominator by $3$ , we get $10$ . Therefore, the constant of proportionality for option B is $10$ .
Option C: Simplify Fraction: For option C, $y = \frac{12}{2}x$ , we simplify the fraction $\frac{12}{2}$ to get the constant of proportionality. Dividing both the numerator and the denominator by $2$ , we get $6$ . Therefore, the constant of proportionality for option C is $6$ .
Option D: Simplify Fraction: For option D, $y = \frac{5}{5}x$ , we simplify the fraction $\frac{5}{5}$ to get the constant of proportionality. Dividing both the numerator and the denominator by $5$ , we get $1$ . Therefore, the constant of proportionality for option D is $1$ .