Q. When graphed in the xy-plane, the function f(x)=3(2)x+1 has a y-intercept at (0,k). What is the value of k ?Choose 1 answer:(A) 1(B) 2(C) 3(D) 4
Evaluate at x=0: To find the y-intercept of the function, we need to evaluate the function at x=0. The y-intercept occurs where the graph of the function crosses the y-axis, which is when x=0.
Substitute x=0: Substitute x=0 into the function f(x)=3(2)x+1 to find the value of k.f(0)=3(2)0+1
Calculate 20: Calculate the value of 2 raised to the power of 0, which is 1. 20=1
Multiply by 3: Multiply 3 by the result from the previous step.3×1=3
Add 1: Add 1 to the result from the previous step to find the value of k. 3+1=4
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