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When a number is increased by
2%, the result is 92 . What is the original number to the nearest tenth?
Answer:

When a number is increased by $2 \%$ , the result is $92$ . What is the original number to the nearest tenth? $\newline$ Answer:

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Find the total given a part and a percent

Full solution

Q. When a number is increased by

2 \%

, the result is

92

. What is the original number to the nearest tenth?

\newline

Answer:

Understand the problem: Understand the problem. $\newline$ We need to find the original number before a $2\%$ increase that results in $92$ . $\newline$ To do this, we can set up an equation where the original number plus $2\%$ of the original number equals $92$ . $\newline$ Let's denote the original number as $x$ . $\newline$ The equation will be $x + 0.02x = 92$ .
Combine like terms: Combine like terms in the equation. $\newline$ We can combine $x$ and $0.02x$ to get $1.02x$ , since $0.02x$ is just $2\%$ of $x$ . $\newline$ So the equation becomes $1.02x = 92$ .
Solve for x: Solve for x. $\newline$ To find $x$ , we need to divide both sides of the equation by $1.02$ . $\newline$ $x = \frac{92}{1.02}$
Perform the division: Perform the division to find the original number. $\newline$ $x = \frac{92}{1.02}$ $\newline$ $x \approx 90.1961$
Round the result: Round the result to the nearest tenth. $\newline$ The original number rounded to the nearest tenth is approximately $90.2$ .

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