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When a number is increased by
10%, the result is 92 . What is the original number to the nearest tenth?
Answer:

When a number is increased by $10 \%$ , the result is $92$ . What is the original number to the nearest tenth? $\newline$ Answer:

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Find the total given a part and a percent

Full solution

Q. When a number is increased by

10 \%

, the result is

92

. What is the original number to the nearest tenth?

\newline

Answer:

Understand and Set Up Equation: Understand the problem and set up the equation. $\newline$ We are given that when a number is increased by $10\%$ , the result is $92$ . We need to find the original number. Let's denote the original number as $x$ . The increase of $10\%$ on $x$ can be represented as $x + 0.10x$ , which equals $92$ . $\newline$ So, the equation is $x + 0.10x = 92$ .
Combine Like Terms: Combine like terms in the equation. $\newline$ We can combine $x$ and $0.10x$ to get $1.10x$ , since $0.10x$ is the same as $10\%$ of $x$ . $\newline$ The equation now is $1.10x = 92$ .
Solve for x: Solve for x. $\newline$ To find $x$ , we need to divide both sides of the equation by $1.10$ . $\newline$ $x = \frac{92}{1.10}$
Perform Division: Perform the division to find the original number. $x = \frac{92}{1.10} = 83.6363636364$
Round to Nearest Tenth: Round the result to the nearest tenth. $\newline$ The original number rounded to the nearest tenth is $83.6$ .

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