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What value of zz is a solution to this equation?\newline15+z=2215 + z = 22\newlineChoices:\newline(A)z=7z = 7\newline(B)z=8z = 8

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Full solution

Q. What value of zz is a solution to this equation?\newline15+z=2215 + z = 22\newlineChoices:\newline(A)z=7z = 7\newline(B)z=8z = 8
  1. Isolate z: Step 11: Isolate z in the equation.\newlineGiven equation: 15+z=2215 + z = 22.\newlineSubtract 1515 from both sides to isolate z:\newlinez=22−15z = 22 - 15.\newlineCalculation: z=7z = 7.
  2. Check calculated value: Step 22: Check if the calculated value of zz matches any of the given choices.\newlineChoices are:\newline(A) z=7z = 7\newline(B) z=8z = 8\newlineOur calculated value is z=7z = 7, which matches choice (A).

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