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What value of yy is a solution to this equation?\newliney+5=5y + 5 = 5\newlineChoices:\newline(A)y=0y = 0\newline(B)y=2y = 2

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Q. What value of yy is a solution to this equation?\newliney+5=5y + 5 = 5\newlineChoices:\newline(A)y=0y = 0\newline(B)y=2y = 2
  1. Perform Subtraction: After performing the subtraction, we get: y=0y = 0 This simplifies the equation and gives us the value of yy.
  2. Check Solution: Now we check our solution by substituting y=0y = 0 back into the original equation to see if it holds true.\newline0+5=50 + 5 = 5\newline5=55 = 5\newlineThis is a true statement, so there is no math error.

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