Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
AI tutor
Welcome to Bytelearn!
Let’s check out your problem:
What value of
s
s
s
is a solution to this equation?
\newline
20
+
s
=
24
20 + s = 24
20
+
s
=
24
\newline
Choices:
\newline
(A)
s
=
4
s = 4
s
=
4
\newline
(B)
s
=
5
s = 5
s
=
5
View step-by-step help
Home
Math Problems
Algebra 2
Solve complex trigonomentric equations
Full solution
Q.
What value of
s
s
s
is a solution to this equation?
\newline
20
+
s
=
24
20 + s = 24
20
+
s
=
24
\newline
Choices:
\newline
(A)
s
=
4
s = 4
s
=
4
\newline
(B)
s
=
5
s = 5
s
=
5
Simplify the equation:
Now, we simplify both sides of the equation.
\newline
s
=
24
−
20
s = 24 - 20
s
=
24
−
20
\newline
s
=
4
s = 4
s
=
4
Verify the solution:
We check our solution by substituting
s
=
4
s = 4
s
=
4
back into the original equation to verify if it satisfies the equation.
\newline
20
+
4
=
24
20 + 4 = 24
20
+
4
=
24
\newline
24
=
24
24 = 24
24
=
24
More problems from Solve complex trigonomentric equations
Question
Find all solutions with
0
∘
≤
θ
≤
18
0
∘
0^\circ \leq \theta \leq 180^\circ
0
∘
≤
θ
≤
18
0
∘
. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.
\newline
cos
(
θ
)
=
−
1
\cos(\theta) = -1
cos
(
θ
)
=
−
1
\newline
‾
∘
\underline{\hspace{2em}}^\circ
∘
Get tutor help
Posted 7 months ago
Question
Kimi's school is
15
15
15
kilometers west of her house and
8
8
8
kilometers south of her friend Franklin's house. Every day, Kimi bicycles from her house to her school. After school, she bicycles from her school to Franklin's house. Before dinner, she bicycles home on a bike path that goes straight from Franklin's house to her own house. How far does Kimi bicycle each day?
\newline
_
_
_
_
_
\_\_\_\_\_
_____
kilometers
Get tutor help
Posted 7 months ago
Question
Evaluate. Write your answer as an integer or as a decimal rounded to the nearest hundredth.
\newline
cos
3
5
∘
=
\cos 35^\circ =
cos
3
5
∘
=
__
Get tutor help
Posted 7 months ago
Question
Find all solutions with
−
9
0
∘
≤
θ
≤
9
0
∘
-90^\circ \leq \theta \leq 90^\circ
−
9
0
∘
≤
θ
≤
9
0
∘
. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.
\newline
csc
(
θ
)
=
−
1
\csc(\theta) = -1
csc
(
θ
)
=
−
1
\newline
_
_
_
_
∘
\_\_\_\_\,^\circ
____
∘
Get tutor help
Posted 8 months ago
Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.
\newline
cot
3
0
∘
=
\cot 30^\circ =
cot
3
0
∘
=
______
Get tutor help
Posted 7 months ago
Question
The terminal side of an angle
θ
\theta
θ
in standard position intersects the unit circle at
(
84
85
,
13
85
)
(\frac{84}{85}, \frac{13}{85})
(
85
84
,
85
13
)
. What is
cos
(
θ
)
\cos(\theta)
cos
(
θ
)
?
\newline
Write your answer in simplified, rationalized form.
\newline
______
Get tutor help
Posted 7 months ago
Question
−
9
0
∘
<
θ
<
9
0
∘
-90^\circ < \theta < 90^\circ
−
9
0
∘
<
θ
<
9
0
∘
. Find the value of
θ
\theta
θ
in degrees.
\newline
tan
(
θ
)
=
0
\tan(\theta) = 0
tan
(
θ
)
=
0
\newline
Write your answer in simplified, rationalized form. Do not round.
\newline
θ
=
\theta =
θ
=
____
∘
^\circ
∘
\newline
Get tutor help
Posted 8 months ago
Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.
\newline
csc
6
0
∘
=
\csc 60^\circ =
csc
6
0
∘
=
______
Get tutor help
Posted 8 months ago
Question
θ
\theta
θ
is an acute angle. Find the value of
θ
\theta
θ
in degrees.
\newline
sec
(
θ
)
=
2
\sec(\theta) = \sqrt{2}
sec
(
θ
)
=
2
\newline
θ
=
\theta =
θ
=
____
°
\degree
°
Get tutor help
Posted 7 months ago
Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.
\newline
cos
9
0
∘
=
\cos 90^\circ =
cos
9
0
∘
=
____
Get tutor help
Posted 8 months ago
Related topics
Algebra - Order of Operations
Algebra - Distributive Property
`X` and `Y` Axes
Geometry - Scalene Triangle
Common Multiple
Geometry - Quadrant