What value of p is a solution to this equation? p - 2 = 6 Choices: (A)p = 8 (B)p = 9

Addition to cancel -2: Given the equation p - 2 = 6, we want to isolate p to find its value. To do this, we add 2 to both sides of the equation to cancel out the -2 on the left side. p - 2 + 2 = 6 + 2Solve for p: After performing the addition, we get: p = 8 This is the value of p that satisfies the equation.Check solution: We check the answer by substituting p = 8 back into the original equation to see if it holds true: 8 - 2 = 6 6 = 6 This is a true statement, so there is no math error.

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What value of $p$ is a solution to this equation? $\newline$ $p - 2 = 6$ $\newline$ Choices: $\newline$ (A) $p = 8$ $\newline$ (B) $p = 9$

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Algebra 2

Solve complex trigonomentric equations

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Q. What value of

p

is a solution to this equation?

\newline

p - 2 = 6

\newline

Choices:

\newline

(A)

p = 8

\newline

(B)

p = 9

Addition to cancel $-2$ : Given the equation $p - 2 = 6$ , we want to isolate $p$ to find its value. $\newline$ To do this, we add $2$ to both sides of the equation to cancel out the $-2$ on the left side. $\newline$ $p - 2 + 2 = 6 + 2$
Solve for $p$ : After performing the addition, we get: $p = 8$ This is the value of $p$ that satisfies the equation.
Check solution: We check the answer by substituting $p = 8$ back into the original equation to see if it holds true: $\newline$ $8 - 2 = 6$ $\newline$ $6 = 6$ $\newline$ This is a true statement, so there is no math error.