What value of b is a solution to this equation? 2 + b = 3 Choices: (A)b = 0 (B)b = 1

Subtract to isolate b: To find the value of b that solves the equation, we need to isolate b on one side of the equation. We can do this by subtracting 2 from both sides of the equation. Calculation: 2 + b - 2 = 3 - 2Simplified equation: After performing the subtraction, we get the simplified equation: b = 1Check possible choices: We check the possible choices to see which one matches our solution. Choices: (A) b = 0 (B) b = 1 Our calculation shows that b = 1, which corresponds to choice (B).

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What value of $b$ is a solution to this equation? $\newline$ $2 + b = 3$ $\newline$ Choices: $\newline$ (A) $b = 0$ $\newline$ (B) $b = 1$

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Algebra 2

Solve complex trigonomentric equations

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Q. What value of

b

is a solution to this equation?

\newline

2 + b = 3

\newline

Choices:

\newline

(A)

b = 0

\newline

(B)

b = 1

Subtract to isolate $b$ : To find the value of $b$ that solves the equation, we need to isolate $b$ on one side of the equation. We can do this by subtracting $2$ from both sides of the equation. $\newline$ Calculation: $2 + b - 2 = 3 - 2$
Simplified equation: After performing the subtraction, we get the simplified equation: $b = 1$
Check possible choices: We check the possible choices to see which one matches our solution. $\newline$ Choices: $\newline$ (A) $b = 0$ $\newline$ (B) $b = 1$ $\newline$ Our calculation shows that $b = 1$ , which corresponds to choice (B).