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What value of aa is a solution to this equation?\newlinea+20=32a + 20 = 32\newlineChoices:\newline(A)a=10a = 10\newline(B)a=12a = 12

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Full solution

Q. What value of aa is a solution to this equation?\newlinea+20=32a + 20 = 32\newlineChoices:\newline(A)a=10a = 10\newline(B)a=12a = 12
  1. Isolate variable 'a': Step 11: Isolate the variable 'a' in the equation.\newlineGiven equation: a+20=32a + 20 = 32.\newlineSubtract 2020 from both sides to isolate 'a':\newlinea+20−20=32−20a + 20 - 20 = 32 - 20,\newlinea=12a = 12.
  2. Check solution: Step 22: Check the solution by substituting aa back into the original equation.\newlineSubstitute a=12a = 12 into the original equation:\newline12+20=3212 + 20 = 32,\newline32=3232 = 32.

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