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Let’s check out your problem:
What is
y
=
−
1
3
x
−
9
y=-\frac{1}{3}x-9
y
=
−
3
1
x
−
9
written in standard form?
\newline
Choose
1
1
1
answer:
\newline
(A)
x
+
3
y
=
−
27
x+3y=-27
x
+
3
y
=
−
27
\newline
(B)
y
=
−
1
3
(
x
+
27
)
y=-\frac{1}{3}(x+27)
y
=
−
3
1
(
x
+
27
)
\newline
(C)
3
y
=
−
x
−
27
3y=-x-27
3
y
=
−
x
−
27
\newline
(D)
1
3
x
+
y
+
9
=
0
\frac{1}{3}x+y+9=0
3
1
x
+
y
+
9
=
0
View step-by-step help
Home
Math Problems
Algebra 1
Power rule with rational exponents
Full solution
Q.
What is
y
=
−
1
3
x
−
9
y=-\frac{1}{3}x-9
y
=
−
3
1
x
−
9
written in standard form?
\newline
Choose
1
1
1
answer:
\newline
(A)
x
+
3
y
=
−
27
x+3y=-27
x
+
3
y
=
−
27
\newline
(B)
y
=
−
1
3
(
x
+
27
)
y=-\frac{1}{3}(x+27)
y
=
−
3
1
(
x
+
27
)
\newline
(C)
3
y
=
−
x
−
27
3y=-x-27
3
y
=
−
x
−
27
\newline
(D)
1
3
x
+
y
+
9
=
0
\frac{1}{3}x+y+9=0
3
1
x
+
y
+
9
=
0
Rewrite equation in standard form:
Rewrite the equation
y
=
−
1
3
x
−
9
y = -\frac{1}{3}x - 9
y
=
−
3
1
x
−
9
in standard form, which generally looks like
A
x
+
B
y
+
C
=
0
Ax + By + C = 0
A
x
+
B
y
+
C
=
0
.
Eliminate fraction by multiplication:
Multiply every term by
3
3
3
to eliminate the
fraction
.
Rearrange terms on one side:
Rearrange the equation to get all terms on one side.
Match with given options:
Check the options given to match the derived equation.
More problems from Power rule with rational exponents
Question
Simplify.
\newline
8
1
1
2
81^{\frac{1}{2}}
8
1
2
1
\newline
_____________
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Question
Simplify.
\newline
(
−
32
)
1
/
5
(-32)^{1/5}
(
−
32
)
1/5
\newline
______
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Posted 1 year ago
Question
Simplify. Assume all variables are positive.
\newline
w
4
3
w
7
3
\frac{w^{\frac{4}{3}}}{w^{\frac{7}{3}}}
w
3
7
w
3
4
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
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Posted 9 months ago
Question
Simplify. Assume all variables are positive.
\newline
(
2
r
1
3
)
8
(2r^{\frac{1}{3}})^8
(
2
r
3
1
)
8
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
Get tutor help
Posted 9 months ago
Question
Simplify. Assume all variables are positive.
\newline
v
7
4
⋅
v
9
4
v^{\frac{7}{4}} \cdot v^{\frac{9}{4}}
v
4
7
⋅
v
4
9
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
Get tutor help
Posted 9 months ago
Question
Simplify.
\newline
1
1
4
⋅
1
1
4
1^{\frac{1}{4}} \cdot 1^{\frac{1}{4}}
1
4
1
⋅
1
4
1
\newline
______
Get tutor help
Posted 9 months ago
Question
Simplify.
\newline
3
2
(
−
1
/
5
)
32^{(-1/5)}
3
2
(
−
1/5
)
Get tutor help
Posted 1 year ago
Question
Simplify. Assume all variables are positive.
\newline
w
3
2
w
5
2
\frac{w^{\frac{3}{2}}}{w^{\frac{5}{2}}}
w
2
5
w
2
3
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
Get tutor help
Posted 1 year ago
Question
Simplify. Assume all variables are positive.
\newline
(
27
x
)
2
3
(27x)^{\frac{2}{3}}
(
27
x
)
3
2
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
Get tutor help
Posted 1 year ago
Question
Simplify. Assume all variables are positive.
\newline
x
1
4
x
11
4
\frac{x^{\frac{1}{4}}}{x^{\frac{11}{4}}}
x
4
11
x
4
1
\newline
\newline
Write your answer in the form
A
A
A
or
A
B
\frac{A}{B}
B
A
, where
A
A
A
and
B
B
B
are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.
\newline
______
\newline
Get tutor help
Posted 1 year ago
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