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What is the volume of a sphere with a radius of 
53.9in, rounded to the nearest tenth of a cubic inch?
Answer: in 
^(3)

What is the volume of a sphere with a radius of 53.9 53.9 in\mathrm{in} , rounded to the nearest tenth of a cubic inch?\newlineAnswer: in\text{in} 3 ^{3}

Full solution

Q. What is the volume of a sphere with a radius of 53.9 53.9 in\mathrm{in} , rounded to the nearest tenth of a cubic inch?\newlineAnswer: in\text{in} 3 ^{3}
  1. Recall formula for volume: Recall the formula for the volume of a sphere.\newlineThe formula for the volume of a sphere is V=43πr3V = \frac{4}{3}\pi r^3, where VV is the volume and rr is the radius of the sphere.
  2. Substitute given radius: Substitute the given radius into the formula.\newlineThe given radius is r=53.9r = 53.9 inches. Plugging this value into the formula gives us V=43π(53.9)3V = \frac{4}{3}\pi(53.9)^3.
  3. Calculate volume: Calculate the volume using the given radius. V=43π(53.9)3=43π(53.9×53.9×53.9)V = \frac{4}{3}\pi(53.9)^3 = \frac{4}{3}\pi(53.9 \times 53.9 \times 53.9)
  4. Perform multiplication: Perform the multiplication.\newlineV=(43)π(53.9×53.9×53.9)=(43)π(156.161×53.9)=(43)π(8415.0879)V = \left(\frac{4}{3}\right)\pi(53.9 \times 53.9 \times 53.9) = \left(\frac{4}{3}\right)\pi(156.161 \times 53.9) = \left(\frac{4}{3}\right)\pi(8415.0879)

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