What is the value of A when we rewrite (65)x as [A−8x] ?A) \left(\dfrac{5}{6}\right)^{−8}B) \left(\dfrac{6}{5}\right)^{8}C) \left(\dfrac{5}{6}\right)^{8}D) \left(\dfrac{6}{5}\right)^{−8}
Q. What is the value of A when we rewrite (65)x as [A−8x] ?A) \left(\dfrac{5}{6}\right)^{−8}B) \left(\dfrac{6}{5}\right)^{8}C) \left(\dfrac{5}{6}\right)^{8}D) \left(\dfrac{6}{5}\right)^{−8}
Rewrite in desired form: First, we need to rewrite (65)x in the form A−8x.
Equating exponents: We know that (65)x=A−8x.
Solving for A: To find A, we need to equate the exponents. So, (65)=A−8.
Finding A value: Take the 8th root of both sides to solve for A. So, A=(65)−1/8.
Simplify the expression: Simplify the expression. A=(56)1/8.
More problems from Find limits involving factorization and rationalization