Q. What is the total number of different 9-letter arrangements that can be formed using the letters in the word PERIMETER?Answer:
Question Prompt: Question_prompt: How many different 9-letter arrangements can be formed from the word PERIMETER?
Count Letters: First, count the number of each letter in PERIMETER. We have P(1), E(3), R(2), I(1), M(1), T(1).
Formula for Arrangements: The formula for the number of arrangements of a word with repeated letters is n1!×n2!×…×nk!n!, where n is the total number of letters, and n1,n2,…,nk are the frequencies of the repeated letters.
Calculate Total Factorial: Calculate the factorial of the total number of letters: 9!=9×8×7×6×5×4×3×2×1.
Calculate Factorial for Repeated Letters: Calculate the factorial for each of the repeated letters: E(3) so 3!, R(2) so 2!, and the rest are unique so their factorials are 1.
Plug Values into Formula: Now plug these values into the formula: 9!/(3!×2!×1!×1!×1!×1!)=(9×8×7×6×5×4×3×2×1)/((3×2×1)×(2×1)).
Simplify Calculation: Simplify the calculation: 3!×2!9!=(6×2)(9×8×7×6×5×4×3×2×1)=1(9×8×7×5×4×3×1).
Finish Calculation: Finish the calculation: 9×8×7×5×4×3=30240.
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