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What is the total number of different 8-letter arrangements that can be formed using the letters in the word PARADIGM?
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What is the total number of different 88-letter arrangements that can be formed using the letters in the word PARADIGM?\newlineAnswer:

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Q. What is the total number of different 88-letter arrangements that can be formed using the letters in the word PARADIGM?\newlineAnswer:
  1. Identify Letters Count: Identify the number of each letter in the word PARADIGM.\newlineThe word PARADIGM has 88 letters with the following counts:\newlineP - 11, A - 22, R - 11, D - 11, I - 11, G - 11, M - 11.
  2. Calculate Total Arrangements: Calculate the total number of arrangements without considering the repetition of the letter 'A'.\newlineIf all letters were distinct, the number of different arrangements of 88 letters would be 8!8! (88 factorial).\newline8!=8×7×6×5×4×3×2×1=40,3208! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40,320.
  3. Adjust for Repetition: Adjust for the repetition of the letter 'A'.\newlineSince the letter 'A' repeats twice, we need to divide the total number of arrangements by the number of ways to arrange these two 'A's among themselves to avoid overcounting.\newlineThe number of ways to arrange two 'A's is 2!2! (22 factorial).\newline2!=2×1=22! = 2 \times 1 = 2.
  4. Calculate Final Arrangements: Calculate the final number of different arrangements.\newlineTo find the total number of different 88-letter arrangements, divide the total number of arrangements from Step 22 by the number of arrangements of repeated letters from Step 33.\newlineTotal number of different arrangements = 8!2!=40,3202=20,160\frac{8!}{2!} = \frac{40,320}{2} = 20,160.

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