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What is the total number of different 11-letter arrangements that can be formed using the letters in the word FUNDAMENTAL?
Answer:

What is the total number of different 1111-letter arrangements that can be formed using the letters in the word FUNDAMENTAL?\newlineAnswer:

Full solution

Q. What is the total number of different 1111-letter arrangements that can be formed using the letters in the word FUNDAMENTAL?\newlineAnswer:
  1. Count Letters: First, count the number of each letter in FUNDAMENTAL. We got FF, UU, NN, DD, AA, MM, EE, NN, TT, AA, UU00. Notice that NN appears twice and AA appears twice.
  2. Calculate Formula: Since the word FUNDAMENTAL has 1111 letters with 22 Ns and 22 As, the formula for the number of arrangements is 11!(2!×2!)\frac{11!}{(2! \times 2!)}.
  3. Calculate 11!11!: Calculate 11!11! which is 11×10×9×8×7×6×5×4×3×2×111 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1.
  4. Calculate 2!2!: Calculate 2!2! which is 2×12 \times 1, and since we have two 2!2!s, it's (2×1)×(2×1)(2 \times 1) \times (2 \times 1).
  5. Divide Factorial: Now divide 11!11! by the product of the two 2!2!s. So, it's (11×10×9×8×7×6×5×4×3×2×1)/((2×1)×(2×1))(11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1) / ((2 \times 1) \times (2 \times 1)).
  6. Perform Division: Perform the division to get the number of arrangements. The calculation is (11×10×9×8×7×6×5×4×3×2×1)/(2×2)(11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1) / (2 \times 2).
  7. Simplify Result: The result is 11×10×9×8×7×6×5×4×3×2×1/411 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 / 4. Simplify this to get $\(11\) \times \(10\) \times \(9\) \times \(8\) \times \(7\) \times \(6\) \times \(5\) \times \(4\) \times \(3\) \times \(2\) \times \(1\) / \(4\) = \(11\) \times \(10\) \times \(9\) \times \(8\) \times \(7\) \times \(6\) \times \(5\) \times \(4\) \times \(3\) \times \(2\) \times \(1\) / \(4\) = \(11\) \times \(10\) \times \(9\) \times \(8\) \times \(7\) \times \(6\) \times \(5\) \times \(2\) \times \(3\) \times \(2\) \times \(1\).

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