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What is the total number of different 10-letter arrangements that can be formed using the letters in the word HYPOTENUSE?
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What is the total number of different 1010-letter arrangements that can be formed using the letters in the word HYPOTENUSE?\newlineAnswer:

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Q. What is the total number of different 1010-letter arrangements that can be formed using the letters in the word HYPOTENUSE?\newlineAnswer:
  1. Identify Letters Count: Identify the number of each letter in the word HYPOTENUSE.\newlineH - 11, Y - 11, P - 11, O - 11, T - 11, E - 22, N - 11, U - 11, S - 11
  2. Calculate Factorial: Calculate the factorial of the number of letters in the word. Since there are 1010 letters in the word HYPOTENUSE, we calculate 10!10! (1010 factorial).\newline10!=10×9×8×7×6×5×4×3×2×1=3,628,80010! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 3,628,800
  3. Adjust for Repeated Letters: Adjust for the repeated letters. Since the letter 'E' appears twice, we need to divide the total by the factorial of the number of times 'E' appears to correct for overcounting.\newlineWe divide by 2!2! because 'E' appears twice.\newline2!=2×1=22! = 2 \times 1 = 2
  4. Calculate Final Arrangements: Calculate the final number of arrangements by dividing the total number of arrangements by the number of repeated letter arrangements.\newlineNumber of arrangements = 10!2!\frac{10!}{2!}\newlineNumber of arrangements = 3,628,8002=1,814,400\frac{3,628,800}{2} = 1,814,400

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