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What is the slope of the line through (−10,1)(-10,1) and (0,−4)(0, -4)?

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Full solution

Q. What is the slope of the line through (−10,1)(-10,1) and (0,−4)(0, -4)?
  1. Label Points: To find the slope of the line through two points, we use the slope formula, which is (change in yy) / (change in xx), or (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Let's label our points: point 11 is (−10,1)(-10, 1) and point 22 is (0,−4)(0, -4). So, x1=−10x_1 = -10, y1=1y_1 = 1, x2=0x_2 = 0, and y2=−4y_2 = -4.
  2. Plug Values: Now we will plug these values into the slope formula: slope m=(y2−y1)(x2−x1)=(−4−1)(0−(−10))m = \frac{(y_2 - y_1)}{(x_2 - x_1)} = \frac{(-4 - 1)}{(0 - (-10))}.
  3. Simplify Formula: Simplify the numerator and denominator: slope m=(−4−1)(0+10)=−510m = \frac{(-4 - 1)}{(0 + 10)} = \frac{-5}{10}.
  4. Final Slope: Now we simplify the fraction −510-\frac{5}{10} to get the slope. −510-\frac{5}{10} simplifies to −12-\frac{1}{2}.

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