What is the slope of the line? 5(y+2)=4(x-3) Choose 1 answer: (A) (2)/(3) (B) (4)/(5) (C) (5)/(4) (D) (3)/(2)

Rewrite Equation: First, we need to rewrite the equation in slope-intercept form, which is y = mx + b, where m is the slope. 5(y + 2) = 4(x - 3) Distribute 5 to both terms inside the parentheses on the left side and 4 to both terms inside the parentheses on the right side. 5y + 10 = 4x - 12Isolate y: Next, we need to isolate y on one side of the equation to get it into slope-intercept form. Subtract 10 from both sides of the equation to move the constant term to the right side. 5y = 4x - 12 - 10 5y = 4x - 22Solve for y: Now, divide every term by 5 to solve for y. y = (4/5)x - 22/5 The coefficient of x, which is 4/5, is the slope of the line.

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What is the slope of the line?

5(y+2)=4(x-3)
Choose 1 answer:
(A)
(2)/(3)
(B)
(4)/(5)
(C)
(5)/(4)
(D)
(3)/(2)

What is the slope of the line? $\newline$ $5(y+2)=4(x-3)$ $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{2}{3}$ $\newline$ (B) $\frac{4}{5}$ $\newline$ (C) $\frac{5}{4}$ $\newline$ (D) $\frac{3}{2}$

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Q. What is the slope of the line?

\newline

5(y+2)=4(x-3)

\newline

Choose

1

answer:

\newline

(A)

\frac{2}{3}

\newline

(B)

\frac{4}{5}

\newline

(C)

\frac{5}{4}

\newline

(D)

\frac{3}{2}

Rewrite Equation: First, we need to rewrite the equation in slope-intercept form, which is $y = mx + b$ , where $m$ is the slope. $5(y + 2) = 4(x - 3)$ Distribute $5$ to both terms inside the parentheses on the left side and $4$ to both terms inside the parentheses on the right side. $5y + 10 = 4x - 12$
Isolate y: Next, we need to isolate $y$ on one side of the equation to get it into slope-intercept form. $\newline$ Subtract $10$ from both sides of the equation to move the constant term to the right side. $\newline$ $5y = 4x - 12 - 10$ $\newline$ $5y = 4x - 22$
Solve for y: Now, divide every term by $5$ to solve for $y$ . $\newline$ $y = \left(\frac{4}{5}\right)x - \frac{22}{5}$ $\newline$ The coefficient of $x$ , which is $\frac{4}{5}$ , is the slope of the line.