What is the midline equation of {:[y=8cos(5pi x+(3pi)/(2))-9?],[y=◻]:}

Identify Midline: The midline of a trigonometric function of the form y = A*cos(Bx + C) + D or y = A*sin(Bx + C) + D is the horizontal line y = D, where D is the vertical shift of the function.Determine Function Parameters: In the given function y = 8cos(5pi x + (3pi)/(2)) - 9, the coefficient A is 8, B is 5pi, C is (3pi)/(2), and the vertical shift D is -9.Calculate Midline Equation: Therefore, the midline equation of the given function is the horizontal line y = -9.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the midline equation of

{:[y=8cos(5pi x+(3pi)/(2))-9?],[y=◻]:}

What is the midline equation of $\newline$ $\begin{array}{l} y=8 \cos \left(5 \pi x+\frac{3 \pi}{2}\right)-9 ? \\ y=\square \end{array}$

View step-by-step help

Home

Math Problems

Grade 6

Multiply using the distributive property

Full solution

Q. What is the midline equation of

\newline

\begin{array}{l} y=8 \cos \left(5 \pi x+\frac{3 \pi}{2}\right)-9 ? \\ y=\square \end{array}

Identify Midline: The midline of a trigonometric function of the form $y = A\cos(Bx + C) + D$ or $y = A\sin(Bx + C) + D$ is the horizontal line $y = D$ , where $D$ is the vertical shift of the function.
Determine Function Parameters: In the given function $y = 8\cos(5\pi x + \frac{3\pi}{2}) - 9$ , the coefficient $A$ is $8$ , $B$ is $5\pi$ , $C$ is $\frac{3\pi}{2}$ , and the vertical shift $D$ is $-9$ .
Calculate Midline Equation: Therefore, the midline equation of the given function is the horizontal line $y = -9$ .