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What is the inverse of the function

{:[h(x)=(3-x)/(x+1)" ? "],[h^(-1)(x)=◻]:}

What is the inverse of the function h(x)=3xx+1 h(x) = \frac{3-x}{x+1} ? h1(x)= h^{-1}(x) = \square

Full solution

Q. What is the inverse of the function h(x)=3xx+1 h(x) = \frac{3-x}{x+1} ? h1(x)= h^{-1}(x) = \square
  1. Understand Inverse Function: Understand the concept of an inverse function. An inverse function, denoted as h1(x)h^{-1}(x), is a function that reverses the effect of the original function h(x)h(x). To find the inverse, we swap the roles of xx and yy in the original function and then solve for yy.
  2. Write Original Function: Write the original function with yy instead of h(x)h(x). Let y=3xx+1y = \frac{3-x}{x+1}. We will solve for xx in terms of yy to find the inverse function.
  3. Swap xx and yy: Swap xx and yy to find the inverse.\newlineReplace yy with xx and xx with yy to get the equation for the inverse function: x=3yy+1x = \frac{3-y}{y+1}.
  4. Solve for y: Solve for y in terms of x.\newlineTo find y, we need to isolate it on one side of the equation. Start by multiplying both sides by (y+1)(y+1) to get rid of the denominator: x(y+1)=3yx(y+1) = 3-y.
  5. Distribute xx: Distribute xx on the left side of the equation.xy+x=3yxy + x = 3 - y.
  6. Move Terms: Move all terms involving yy to one side and the constant terms to the other side.\newlineAdd yy to both sides and subtract xx from both sides to get: xy+y=3xxy + y = 3 - x.
  7. Factor out yy: Factor out yy on the left side of the equation.y(x+1)=3x.y(x + 1) = 3 - x.
  8. Divide for yy: Divide both sides by (x+1)(x + 1) to solve for yy.y=3xx+1y = \frac{3 - x}{x + 1}.
  9. Write Inverse Function: Write the inverse function.\newlineThe inverse function is h1(x)=3xx+1h^{-1}(x) = \frac{3 - x}{x + 1}.

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