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What is the equation of the line that passes through the point 
(-6,-2) and has a slope of 
-(2)/(3) ?
Answer:

What is the equation of the line that passes through the point (6,2) (-6,-2) and has a slope of 23 -\frac{2}{3} ?\newlineAnswer:

Full solution

Q. What is the equation of the line that passes through the point (6,2) (-6,-2) and has a slope of 23 -\frac{2}{3} ?\newlineAnswer:
  1. Identify slope and point: Identify the slope and the point through which the line passes. The slope mm is given as 23-\frac{2}{3}, and the point is (6,2)(-6, -2).
  2. Use point-slope form: Use the point-slope form of the equation of a line to start.\newlineThe point-slope form is yy1=m(xx1)y - y_1 = m(x - x_1), where (x1,y1)(x_1, y_1) is a point on the line and mm is the slope.
  3. Substitute point and slope: Substitute the given point and slope into the point-slope form.\newlineUsing the point (6,2)(-6, -2) and the slope 23-\frac{2}{3}, we get:\newliney(2)=23(x(6))y - (-2) = -\frac{2}{3}(x - (-6))
  4. Simplify the equation: Simplify the equation. y+2=23(x+6)y + 2 = -\frac{2}{3}(x + 6)
  5. Distribute the slope: Distribute the slope on the right side of the equation. \newliney+2=23x236y + 2 = -\frac{2}{3}x - \frac{2}{3}\cdot6
  6. Multiply fractions: Multiply the fractions on the right side of the equation. \newliney+2=23x4y + 2 = -\frac{2}{3}x - 4
  7. Isolate y: Isolate y to get the equation in slope-intercept form.\newlineSubtract 22 from both sides of the equation:\newliney=23x42y = -\frac{2}{3}x - 4 - 2\newliney=23x6y = -\frac{2}{3}x - 6

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