Q. What is the equation of the line that passes through the point (−6,−2) and has a slope of −32 ?Answer:
Identify slope and point: Identify the slope and the point through which the line passes. The slope m is given as −32, and the point is (−6,−2).
Use point-slope form: Use the point-slope form of the equation of a line to start.The point-slope form is y−y1=m(x−x1), where (x1,y1) is a point on the line and m is the slope.
Substitute point and slope: Substitute the given point and slope into the point-slope form.Using the point (−6,−2) and the slope −32, we get:y−(−2)=−32(x−(−6))
Simplify the equation: Simplify the equation. y+2=−32(x+6)
Distribute the slope: Distribute the slope on the right side of the equation. y+2=−32x−32⋅6
Multiply fractions: Multiply the fractions on the right side of the equation. y+2=−32x−4
Isolate y: Isolate y to get the equation in slope-intercept form.Subtract 2 from both sides of the equation:y=−32x−4−2y=−32x−6
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