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What is the equation of the line that passes through the point 
(4,-1) and has a slope of 
(5)/(4) ?
Answer:

What is the equation of the line that passes through the point (4,1) (4,-1) and has a slope of 54 \frac{5}{4} ?\newlineAnswer:

Full solution

Q. What is the equation of the line that passes through the point (4,1) (4,-1) and has a slope of 54 \frac{5}{4} ?\newlineAnswer:
  1. Identify Slope-Intercept Form: Identify the slope-intercept form of a line's equation.\newlineThe slope-intercept form of a line's equation is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Find Y-Intercept: Use the given slope and point to find the y-intercept bb. We have the slope m=54m = \frac{5}{4} and a point (x,y)=(4,1)(x, y) = (4, -1). We can plug these values into the slope-intercept form to solve for bb. 1=(54)4+b-1 = \left(\frac{5}{4}\right) \cdot 4 + b
  3. Solve for Y-Intercept: Perform the multiplication and solve for bb.1=5+b-1 = 5 + bNow, subtract 55 from both sides to solve for bb.b=15b = -1 - 5b=6b = -6
  4. Write Line Equation: Write the equation of the line using the slope and y-intercept.\newlineNow that we have the slope m=54m = \frac{5}{4} and the y-intercept b=6b = -6, we can write the equation of the line.\newliney=54x6y = \frac{5}{4}x - 6

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