Q. What is the equation of the line that passes through the point (8,−4) and has a slope of −45 ?Answer:
Identify slope and point: Identify the slope m and the point (x1,y1) through which the line passes.The slope m is given as −45, and the point (x1,y1) is (8,−4).
Use point-slope form: Use the point-slope form of the equation of a line to plug in the values of the slope and the point.The point-slope form is y−y1=m(x−x1).Substitute m=−45, x1=8, and y1=−4 into the equation to get y−(−4)=−45(x−8).
Simplify equation to slope-intercept form: Simplify the equation from the point-slope form to the slope-intercept formy=mx+b.First, distribute the slope −45 across (x−8):y+4=−45x+45⋅8
Isolate y: Continue simplifying the equation by multiplying (5)/(4) by 8.y+4=−(5)/(4)x+10
Isolate y: Continue simplifying the equation by multiplying (5)/(4) by 8.y+4=−(5)/(4)x+10Isolate y to get the equation in slope-intercept form. Subtract 4 from both sides of the equation:y=−(5)/(4)x+10−4y=−(5)/(4)x+6
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