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What is the equation of the line that passes through the point 
(-6,1) and has a slope of 
-(5)/(6) ?
Answer:

What is the equation of the line that passes through the point (6,1) (-6,1) and has a slope of 56 -\frac{5}{6} ?\newlineAnswer:

Full solution

Q. What is the equation of the line that passes through the point (6,1) (-6,1) and has a slope of 56 -\frac{5}{6} ?\newlineAnswer:
  1. Identify slope-intercept form: Identify the slope-intercept form of a line's equation. The slope-intercept form of a line's equation is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Find y-intercept: Use the given slope and point to find the y-intercept bb. We have the slope mm as 56-\frac{5}{6} and a point (6,1)(-6,1) that the line passes through. We can substitute these values into the slope-intercept form to find bb. So, we plug in x=6x = -6, y=1y = 1, and m=56m = -\frac{5}{6} into the equation y=mx+by = mx + b. 1=56×(6)+b1 = -\frac{5}{6} \times (-6) + b
  3. Solve for b: Solve for b.\newline1=5+b1 = 5 + b\newlineSubtract 55 from both sides to isolate bb.\newline15=b1 - 5 = b\newlineb=4b = -4
  4. Write line equation: Write the equation of the line using the slope and y-intercept.\newlineNow that we have the slope m=56m = -\frac{5}{6} and the y-intercept b=4b = -4, we can write the equation of the line.\newlineThe equation is y=56x4y = -\frac{5}{6}x - 4.

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