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What is the equation of the line that passes through the point (7,2) and has a slope of 1 ? Answer:

What is the equation of the line that passes through the point (7,2) (7,2) and has a slope of 11 ?\newlineAnswer:

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Full solution

Q. What is the equation of the line that passes through the point (7,2) (7,2) and has a slope of 11 ?\newlineAnswer:
  1. Identify slope and point: Identify the slope mm and the point (x,y)(x, y) through which the line passes.\newlineWe have:\newlineSlope mm: 11\newlinePoint: (7,2)(7, 2)\newlineWe will use the slope-intercept form of a line, which is y=mx+by = mx + b, to find the equation of the line.
  2. Use point to find y-intercept: Use the point (7,2)(7, 2) to solve for the y-intercept (b)(b). We will plug x=7x = 7, y=2y = 2, and m=1m = 1 into the equation y=mx+by = mx + b and solve for bb. 2=1×7+b2 = 1 \times 7 + b 2=7+b2 = 7 + b 2−7=b2 - 7 = b (b)(b)00
  3. Write equation of line: Write the equation of the line using the slope ( extit{m}) and the y-intercept ( extit{b}) that we have found.\newlineWe have:\newlineSlope ( extit{m}): 11\newliney-intercept ( extit{b}): −5-5\newlineThe equation of the line in slope-intercept form is y=mx+by = mx + b.\newlineSubstitute m=1m = 1 and b=−5b = -5 into the equation.\newliney=1x−5y = 1x - 5

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