What is the domain of this quadratic function? y = x^2 + 12x + 36 Choices: (A){x | x ≤ 0} (B){x | x ≥ 0} (C){x | x ≥ -6} (D)all real numbers

Function Domain Definition: The domain of a function refers to the set of all possible input values (x-values) for which the function is defined. For any quadratic function in the form y = ax^2 + bx + c, where a, b, and c are real numbers, the domain is always all real numbers because you can plug any real number into the function and get a real number out.Quadratic Function Example: To confirm this, we can look at the given quadratic function y = x^2 + 12x + 36. There are no restrictions on the x-values that can be substituted into the function. No matter what x-value we choose, we will always get a real number for y. This is true for all quadratic functions, which are defined for all real numbers.Domain of y = x^2 + 12x + 36: Since there are no restrictions on the x-values and the function is defined for all real numbers, the domain of the function y = x^2 + 12x + 36 is all real numbers.

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What is the domain of this quadratic function? $\newline$ $y = x^2 + 12x + 36$ $\newline$ Choices: $\newline$ (A) $\{x | x \leq 0\}$ $\newline$ (B) $\{x | x \geq 0\}$ $\newline$ (C) $\{x | x \geq -6\}$ $\newline$ (D)all real numbers

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Algebra 1

Domain and range of quadratic functions: equations

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Q. What is the domain of this quadratic function?

\newline

y = x^2 + 12x + 36

\newline

Choices:

\newline

(A)

\{x | x \leq 0\}

\newline

(B)

\{x | x \geq 0\}

\newline

(C)

\{x | x \geq -6\}

\newline

(D)all real numbers

Function Domain Definition: The domain of a function refers to the set of all possible input values ( $x$ -values) for which the function is defined. For any quadratic function in the form $y = ax^2 + bx + c$ , where $a$ , $b$ , and $c$ are real numbers, the domain is always all real numbers because you can plug any real number into the function and get a real number out.
Quadratic Function Example: To confirm this, we can look at the given quadratic function $y = x^2 + 12x + 36$ . There are no restrictions on the $x$ -values that can be substituted into the function. No matter what $x$ -value we choose, we will always get a real number for $y$ . This is true for all quadratic functions, which are defined for all real numbers.
Domain of $y = x^2 + 12x + 36$ : Since there are no restrictions on the $x$ -values and the function is defined for all real numbers, the domain of the function $y = x^2 + 12x + 36$ is all real numbers.