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What is the discriminant of the quadratic equation 
-8x^(2)+8x-3=0 ?
32

-160

-32
160

What is the discriminant of the quadratic equation 8x2+8x3=0 -8 x^{2}+8 x-3=0 ?\newline3232\newline160 -160 \newline32 -32 \newline160160

Full solution

Q. What is the discriminant of the quadratic equation 8x2+8x3=0 -8 x^{2}+8 x-3=0 ?\newline3232\newline160 -160 \newline32 -32 \newline160160
  1. Identify Coefficients: The discriminant of a quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. We need to identify the coefficients aa, bb, and cc from the given equation.
  2. Find Coefficients: In the equation 8x2+8x3=0-8x^2 + 8x - 3 = 0, the coefficient aa is 8-8, the coefficient bb is 88, and the coefficient cc is 3-3.
  3. Calculate Discriminant: Now we will calculate the discriminant using the formula D=b24acD = b^2 - 4ac. Substituting the values we get D=(8)24(8)(3)D = (8)^2 - 4\cdot(-8)\cdot(-3).
  4. Substitute Values: Calculating the discriminant, we have D=644×8×3D = 64 - 4 \times 8 \times 3.
  5. Simplify Calculation: Further simplifying, we get D=6496D = 64 - 96.
  6. Final Result: Finally, we find that D=32D = -32.

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