Q. What is the center of the hyperbola x2−4y2−16=0?(_,_)
Move constant term:x2−4y2−16=0Move the constant term to the right side.x2−4y2=16
Convert to standard form:x2−4y2=16Convert the equation into standard form.Divide both sides of the equation by 16.(x2)/16−(4y2)/16=16/16x2/16−y2/4=1
Find center:x2/16−y2/4=1Find the center of the hyperbola.x2/16−y2/4=1 can be written as (x−0)2/16−(y−0)2/4=1.Here h=0, k=0.Center of the hyperbola: (0,0)
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