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Vlad is playing on a swing set.
His horizontal distance 
D(t) (in 
m ) from the center (where being behind the center means a negative distance) as a function of time 
t (in seconds) can be modeled by a sinusoidal expression of the form 
a*cos(b*t)+d.
At 
t=0, when he pushes off, he is 
1m behind the center, which is as far back as he goes. The swing reaches the center 
(pi)/(6) seconds later.
Find 
D(t).

t should be in radians.

D(t)=◻

Vlad is playing on a swing set.\newlineHis horizontal distance D(t) D(t) (in m) from the center (where being behind the center means a negative distance) as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , when he pushes off, he is 1 m 1 \mathrm{~m} behind the center, which is as far back as he goes. The swing reaches the center π6 \frac{\pi}{6} seconds later.\newlineFind D(t) D(t) .\newlinet t should be in radians.\newlineD(t)= D(t)=\square

Full solution

Q. Vlad is playing on a swing set.\newlineHis horizontal distance D(t) D(t) (in m) from the center (where being behind the center means a negative distance) as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form acos(bt)+d a \cdot \cos (b \cdot t)+d .\newlineAt t=0 t=0 , when he pushes off, he is 1 m 1 \mathrm{~m} behind the center, which is as far back as he goes. The swing reaches the center π6 \frac{\pi}{6} seconds later.\newlineFind D(t) D(t) .\newlinet t should be in radians.\newlineD(t)= D(t)=\square
  1. Identify Amplitude: Identify the amplitude of the sinusoidal function.\newlineThe amplitude aa is the maximum distance from the center, which is given as 1m1\,\text{m} behind the center at t=0t=0.\newlineTherefore, a=1a = 1.
  2. Determine Horizontal Shift: Determine the horizontal shift dd of the sinusoidal function.\newlineSince Vlad starts 11m behind the center and that is the farthest point, the horizontal shift dd is 00.
  3. Determine Period: Determine the period of the sinusoidal function.\newlineWe know that the swing reaches the center (π/6)(\pi/6) seconds later, which is a quarter of the period of a cosine function. To find the full period TT, we multiply this time by 44.\newlineT=(π/6)×4=(2π/3)T = (\pi/6) \times 4 = (2\pi/3) seconds.
  4. Calculate Value of b: Calculate the value of b, which is related to the period of the sinusoidal function. The period TT is related to bb by the formula T=2πbT = \frac{2\pi}{b}. We have T=2π3T = \frac{2\pi}{3}, so we can solve for bb: 2π3=2πb\frac{2\pi}{3} = \frac{2\pi}{b} Cross-multiply to solve for bb: b2π3=2πb \cdot \frac{2\pi}{3} = 2\pi b=2π2π3b = \frac{2\pi}{\frac{2\pi}{3}} b=3b = 3.
  5. Write Sinusoidal Function: Write the sinusoidal function for D(t)D(t). We have a=1a = 1, b=3b = 3, and d=0d = 0. Since Vlad starts 1m1m behind the center, we use a cosine function that starts at its maximum value. The function is: D(t)=acos(bt)+dD(t) = a\cos(b\cdot t) + d D(t)=1cos(3t)+0D(t) = 1\cos(3\cdot t) + 0 D(t)=cos(3t)D(t) = \cos(3\cdot t).

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