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Victoria bought stock in a company two years ago that was worth 
x dollars. During the first year that she owned the stock, it decreased by 
16%. During the second year the value of the stock increased by 
8%. Write an expression in terms of 
x that represents the value of the stock after the two years have passed.
Answer:

Victoria bought stock in a company two years ago that was worth x x dollars. During the first year that she owned the stock, it decreased by 16% 16 \% . During the second year the value of the stock increased by 8% 8 \% . Write an expression in terms of x x that represents the value of the stock after the two years have passed.\newlineAnswer:

Full solution

Q. Victoria bought stock in a company two years ago that was worth x x dollars. During the first year that she owned the stock, it decreased by 16% 16 \% . During the second year the value of the stock increased by 8% 8 \% . Write an expression in terms of x x that represents the value of the stock after the two years have passed.\newlineAnswer:
  1. Calculate stock value after decrease: Calculate the value of the stock after the first year's decrease.\newlineThe stock decreased by 16%16\% in the first year. To find the value after the decrease, we multiply the original value xx by (100%16%)(100\% - 16\%).\newlineValue after first year = x×(10.16)x \times (1 - 0.16)
  2. Simplify expression from Step 11: Simplify the expression from Step 11.\newlineValue after first year = x×0.84x \times 0.84
  3. Calculate stock value after increase: Calculate the value of the stock after the second year's increase.\newlineThe stock increased by 8%8\% in the second year. To find the value after the increase, we multiply the value after the first year by (100%+8%)(100\% + 8\%).\newlineValue after second year = (x×0.84)×(1+0.08)(x \times 0.84) \times (1 + 0.08)
  4. Simplify expression from Step 33: Simplify the expression from Step 33.\newlineValue after second year = x×0.84x \times 0.84 \times 11.0808
  5. Perform final multiplication: Perform the multiplication to get the final expression.\newlineValue after second year = x×0.84×1.08x \times 0.84 \times 1.08
  6. Simplify final expression: Simplify the final expression.\newlineValue after second year = x×0.9072x \times 0.9072

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