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v=14.2(12.5-s) The velocity, v, in meters per second, of an airplane s seconds after landing is given by the equation. What is the best interpretation of 14.2 as shown in the equation? Choose 1 answer: (A) The plane takes 14.2 seconds to stop. B The position of the plane changes 14.2 meters every second. (C) The velocity changes by 14.2 meters per second every second. (D) The velocity of the plane just as it lands is 14.2 meters per second.

v=14.2(12.5−s)v=14.2(12.5-s)\newlineThe velocity, vv, in meters per second, of an airplane ss seconds after landing is given by the equation. What is the best interpretation of 14.214.2 as shown in the equation?\newlineChoose 11 answer:\newline(A) The plane takes 14.214.2 seconds to stop.\newline(B) The position of the plane changes 14.214.2 meters every second.\newline(C) The velocity changes by 14.214.2 meters per second every second.\newline(D) The velocity of the plane just as it lands is 14.214.2 meters per second.

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Q. v=14.2(12.5−s)v=14.2(12.5-s)\newlineThe velocity, vv, in meters per second, of an airplane ss seconds after landing is given by the equation. What is the best interpretation of 14.214.2 as shown in the equation?\newlineChoose 11 answer:\newline(A) The plane takes 14.214.2 seconds to stop.\newline(B) The position of the plane changes 14.214.2 meters every second.\newline(C) The velocity changes by 14.214.2 meters per second every second.\newline(D) The velocity of the plane just as it lands is 14.214.2 meters per second.
  1. Analyze the equation: Analyze the given equation v=14.2(12.5−s)v=14.2(12.5-s).\newlineThe equation describes the velocity vv of an airplane in meters per second, ss seconds after landing. The term 14.214.2 is a constant multiplier of the expression (12.5−s)(12.5-s).
  2. Interpret the constant 14.214.2: Interpret the constant 14.214.2.\newlineSince 14.214.2 is multiplying the term (12.5−s)(12.5-s), it represents the rate at which the velocity changes as time ss changes. This is not the time it takes for the plane to stop, nor the position change, nor the initial velocity of the plane.
  3. Determine correct interpretation: Determine the correct interpretation among the given choices.\newline(A) Incorrect - The plane takes 14.214.2 seconds to stop is a time duration, not a rate of change.\newline(B) Incorrect - The position of the plane changes 14.214.2 meters every second would be a statement about distance, not velocity.\newline(C) Correct - The velocity changes by 14.2 meters per second14.2 \, \text{meters per second} every second is a rate of change of velocity, which matches the role of 14.214.2 in the equation.\newline(D) Incorrect - The velocity of the plane just as it lands is 14.2 meters per second14.2 \, \text{meters per second} would imply that 14.214.2 is the initial velocity, which is not indicated by the equation.

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