Using implicit differentiation, find (dy)/(dx). -5x^(2)y^(4)-4x^(2)y^(3)=3-2x

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Using implicit differentiation, find  (dy)/(dx).  -5x^(2)y^(4)-4x^(2)y^(3)=3-2x

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Differentiate Equation: Differentiate both sides of the equation with respect to x, remembering to use the product rule for terms involving both x and y, and the chain rule for terms involving y since y is a function of x.Left Side Derivative: Differentiate the left side of the equation. The derivative of -5x^2y^4 with respect to x is -10xy^4 - 20x^2y^3(dy/dx) using the product rule. The derivative of -4x^2y^3 with respect to x is -8xy^3 - 12x^2y^2(dy/dx) using the product rule.Right Side Derivative: Differentiate the right side of the equation. The derivative of 3 with respect to x is 0, and the derivative of -2x with respect to x is -2.Write Differentiated Equation: Write down the differentiated equation from Steps 2 and 3: -10xy^4 - 20x^2y^3(dy/dx) - 8xy^3 - 12x^2y^2(dy/dx) = -2.Collect Terms: Collect all terms involving (dy/dx) on one side and move all other terms to the opposite side. This gives us -20x^2y^3(dy/dx) - 12x^2y^2(dy/dx) = -2 + 10xy^4 + 8xy^3.Factor Out (dy/dx): Factor out (dy/dx) from the left side of the equation to get (dy/dx)(-20x^2y^3 - 12x^2y^2) = -2 + 10xy^4 + 8xy^3.Solve for (dy/dx): Solve for (dy/dx) by dividing both sides of the equation by (-20x^2y^3 - 12x^2y^2). This gives us (dy/dx) = (-2 + 10xy^4 + 8xy^3) / (-20x^2y^3 - 12x^2y^2).Simplify (dy/dx): Simplify the expression for (dy/dx) if possible. In this case, we can factor out an x from the numerator and an x^2y^2 from the denominator to get (dy/dx) = (-2/x + 10y^4 + 8y^3) / (-20xy^3 - 12y^2).

Using implicit differentiation, find $\frac{d y}{d x}$ . $\newline$ $-5 x^{2} y^{4}-4 x^{2} y^{3}=3-2 x$

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Using implicit differentiation, find dydx \frac{d y}{d x} dxdy​.\newline−5x2y4−4x2y3=3−2x -5 x^{2} y^{4}-4 x^{2} y^{3}=3-2 x −5x2y4−4x2y3=3−2x

Using implicit differentiation, find $\frac{d y}{d x}$ . $\newline$ $-5 x^{2} y^{4}-4 x^{2} y^{3}=3-2 x$