Use the remainder theorem to find P(3) for P(x)=2x3−4x2−2x+9. Specifically, give the quotient and the remainder for the associated division and the value of P(3). Quotient : □ Remainder =□□P(3)=□
Q. Use the remainder theorem to find P(3) for P(x)=2x3−4x2−2x+9. Specifically, give the quotient and the remainder for the associated division and the value of P(3). Quotient : □ Remainder =□□P(3)=□
Apply Remainder Theorem: Step 1: Apply the remainder theorem to find P(3). The remainder theorem states that the remainder of the division of a polynomial P(x) by (x−c) is P(c). Here, c=3. Calculate P(3)=2(3)3−4(3)2−2(3)+9. = 2(27)−4(9)−6+9 = 54−36−6+9 = 21
Perform Synthetic Division: Step 2: Perform synthetic division to find the quotient and remainder.Divide P(x) by (x−3) using synthetic division.Coefficients of P(x): 2,−4,−2,9Using 3 as the synthetic divisor:\begin{array}{cccc}\(\newline2 & | & 6 & | & 6 & | & 12 (\newline\)\hline2 & | & 2 & | & 4 & | & 21\end{array}\)Quotient: 2x2+2x+4Remainder: 21
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