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Use the following function rule to find f(9)f(9).\newlinef(x)=x+12f(x) = \sqrt{x} + 12\newlinef(9)=f(9) = _____

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Q. Use the following function rule to find f(9)f(9).\newlinef(x)=x+12f(x) = \sqrt{x} + 12\newlinef(9)=f(9) = _____
  1. Identify function rule & input: Identify the function rule and the input value.\newlineWe are given the function rule f(x)=x+12f(x) = \sqrt{x} + 12 and we need to find the value of f(9)f(9).
  2. Substitute input into rule: Substitute the input value into the function rule.\newlineTo find f(9)f(9), we substitute 99 for xx in the function rule:\newlinef(9)=9+12f(9) = \sqrt{9} + 12
  3. Calculate square root: Calculate the square root of the input value.\newlineThe square root of 99 is 33, so we have:\newlinef(9)=3+12f(9) = 3 + 12
  4. Add to get final result: Add the square root to 1212 to get the final result.\newlinef(9)=3+12=15f(9) = 3 + 12 = 15

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