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Let’s check out your problem:
Use the following function rule to find
f
(
77
)
f(77)
f
(
77
)
.
\newline
f
(
x
)
=
6
102
−
x
f(x) = 6\sqrt{102 - x}
f
(
x
)
=
6
102
−
x
\newline
f
(
77
)
=
f(77) =
f
(
77
)
=
_____
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Math Problems
Precalculus
Evaluate functions
Full solution
Q.
Use the following function rule to find
f
(
77
)
f(77)
f
(
77
)
.
\newline
f
(
x
)
=
6
102
−
x
f(x) = 6\sqrt{102 - x}
f
(
x
)
=
6
102
−
x
\newline
f
(
77
)
=
f(77) =
f
(
77
)
=
_____
Identify Function & Input:
Identify the function and the input value.
\newline
We are given the function
f
(
x
)
=
6
102
−
x
f(x) = 6\sqrt{102 - x}
f
(
x
)
=
6
102
−
x
and we need to find the value of
f
(
77
)
f(77)
f
(
77
)
.
Substitute Input:
Substitute the input value into the function.
\newline
To find
f
(
77
)
f(77)
f
(
77
)
, we replace
x
x
x
with
77
77
77
in the function:
\newline
f
(
77
)
=
6
102
−
77
f(77) = 6\sqrt{102 - 77}
f
(
77
)
=
6
102
−
77
Perform Subtraction:
Perform the subtraction inside the
square root
.
\newline
Calculate the value inside the square root:
102
−
77
=
25
102 - 77 = 25
102
−
77
=
25
Evaluate Square Root:
Evaluate the square root.
\newline
Since the square root of
25
25
25
is
5
5
5
, we have:
\newline
25
=
5
\sqrt{25} = 5
25
=
5
Multiply by
6
6
6
:
Multiply the result by
6
6
6
. Now, multiply the square root by
6
6
6
to find
f
(
77
)
f(77)
f
(
77
)
:
f
(
77
)
=
6
×
5
f(77) = 6 \times 5
f
(
77
)
=
6
×
5
Calculate Final Result:
Calculate the final result.
f
(
77
)
=
30
f(77) = 30
f
(
77
)
=
30
More problems from Evaluate functions
Question
What is the domain of this function?
\newline
(
9
,
–
2
)
(
6
,
–
10
)
(
–
3
,
9
)
(
5
,
2
)
(9,–2)(6,–10)(–3,9)(5,2)
(
9
,
–2
)
(
6
,
–10
)
(
–3
,
9
)
(
5
,
2
)
\newline
Choices:
\newline
(
A
)
{
–
3
,
5
,
6
,
9
}
(
B
)
{
–
10
,
–
2
,
2
,
9
}
(
C
)
{
2
,
5
,
6
,
9
}
(
D
)
{
–
6
,
–
3
,
5
,
9
}
(A)\{–3,5,6,9\}\newline(B)\{–10,–2,2,9\}\newline(C)\{2,5,6,9\}\newline(D)\{–6,–3,5,9\}
(
A
)
{
–3
,
5
,
6
,
9
}
(
B
)
{
–10
,
–2
,
2
,
9
}
(
C
)
{
2
,
5
,
6
,
9
}
(
D
)
{
–6
,
–3
,
5
,
9
}
Get tutor help
Posted 10 months ago
Question
Look at this set of ordered pairs:
\newline
(
2
,
14
)
(2, 14)
(
2
,
14
)
\newline
(
10
,
12
)
(10, 12)
(
10
,
12
)
\newline
(
3
,
−
19
)
(3, -19)
(
3
,
−
19
)
\newline
Is this relation a function?
\newline
Choices:
\newline
[[yes]
\text{[[yes]}
[[yes]
[no]]
\text{[no]]}
[no]]
Get tutor help
Posted 10 months ago
Question
Use the following function rule to find
f
(
11
)
f(11)
f
(
11
)
.
\newline
f
(
x
)
=
−
10
−
7
x
f(x) = -10 - 7x
f
(
x
)
=
−
10
−
7
x
\newline
f
(
11
)
=
f(11) =
f
(
11
)
=
_____
Get tutor help
Posted 10 months ago
Question
Find the slope of the line
y
=
−
3
x
−
2
5
y = -3x - \frac{2}{5}
y
=
−
3
x
−
5
2
.
\newline
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Posted 10 months ago
Question
A line has a slope of
3
3
3
and passes through the point
(
−
2
,
−
10
)
(-2,-10)
(
−
2
,
−
10
)
. Write its equation in slope-intercept form.
\newline
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Get tutor help
Posted 10 months ago
Question
What is the range of this function?
\newline
y = |x|
\newline
Choices:
\newline
all real numbers
\text{all real numbers}
all real numbers
\newline
{
y
∣
y
≥
0
}
\{y \mid y \geq 0\}
{
y
∣
y
≥
0
}
\newline
{
y
∣
y
≤
0
}
\{y \mid y \leq 0\}
{
y
∣
y
≤
0
}
\newline
{
y
∣
y
>
0
}
\{y \mid y > 0\}
{
y
∣
y
>
0
}
Get tutor help
Posted 1 year ago
Question
Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is the translation
1
1
1
unit down of
f
(
x
)
=
∣
x
∣
f(x) = |x|
f
(
x
)
=
∣
x
∣
.
\newline
Write your answer in the form
a
∣
x
−
h
∣
+
k
a|x - h| + k
a
∣
x
−
h
∣
+
k
, where
a
a
a
,
h
h
h
, and
k
k
k
are integers.
\newline
g
(
x
)
=
g(x) =
g
(
x
)
=
______
\newline
Get tutor help
Posted 1 year ago
Question
What is the domain of this function?
\newline
(
8
,
–
1
)
(
7
,
–
11
)
(
–
4
,
10
)
(
4
,
3
)
(8,–1)(7,–11)(–4,10)(4,3)
(
8
,
–1
)
(
7
,
–11
)
(
–4
,
10
)
(
4
,
3
)
\newline
Choices:
\newline
(
A
)
{
–
4
,
4
,
7
,
8
}
(A)\{–4,4,7,8\}\newline
(
A
)
{
–4
,
4
,
7
,
8
}
(
B
)
{
–
11
,
–
1
,
3
,
10
}
(B)\{–11,–1,3,10\}\newline
(
B
)
{
–11
,
–1
,
3
,
10
}
(
C
)
{
3
,
4
,
7
,
8
}
(C)\{3,4,7,8\}\newline
(
C
)
{
3
,
4
,
7
,
8
}
(
D
)
{
–
7
,
–
4
,
4
,
8
}
(D)\{–7,–4,4,8\}
(
D
)
{
–7
,
–4
,
4
,
8
}
Get tutor help
Posted 1 year ago
Question
What is the domain of this function?
\newline
(
10
,
–
3
)
(
2
,
–
9
)
(
–
5
,
8
)
(
3
,
1
)
(10,\,–3)(2,\,–9)(–5,\,8)(3,\,1)
(
10
,
–3
)
(
2
,
–9
)
(
–5
,
8
)
(
3
,
1
)
\newline
Choices:
\newline
[
{
–
5
,
2
,
3
,
10
}
]
[
{
–
9
,
–
3
,
1
,
8
}
]
[
{
1
,
2
,
3
,
10
}
]
[
{
–
10
,
–
5
,
2
,
3
}
]
[\{–5,2,3,10\}][\{–9,\,–3,1,8\}][\{1,2,3,10\}][\{–10,\,–5,2,3\}]
[{
–5
,
2
,
3
,
10
}]
[{
–9
,
–3
,
1
,
8
}]
[{
1
,
2
,
3
,
10
}]
[{
–10
,
–5
,
2
,
3
}]
Get tutor help
Posted 10 months ago
Question
What is the domain of this function?
\newline
(
1
,
–
4
)
(
9
,
–
12
)
(
–
6
,
11
)
(
7
,
5
)
(1,–4)(9,–12)(–6,11)(7,5)
(
1
,
–4
)
(
9
,
–12
)
(
–6
,
11
)
(
7
,
5
)
\newline
Choices:
(
A
)
{
–
6
,
1
,
7
,
9
}
\newline\\(A)\{–6,1,7,9\}\newline
(
A
)
{
–6
,
1
,
7
,
9
}
(
B
)
{
–
12
,
–
4
,
5
,
11
}
(B)\{–12,–4,5,11\}\newline
(
B
)
{
–12
,
–4
,
5
,
11
}
(
C
{
5
,
1
,
7
,
9
}
(C\{5,1,7,9\}\newline
(
C
{
5
,
1
,
7
,
9
}
(
D
)
{
–
9
,
–
6
,
1
,
7
}
(D)\{–9,–6,1,7\}
(
D
)
{
–9
,
–6
,
1
,
7
}
Get tutor help
Posted 10 months ago
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