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Use the following function rule to find f(49)f(49).\newlinef(x)=3+xf(x) = 3 + \sqrt{x}\newlinef(49)=f(49) = _____

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Q. Use the following function rule to find f(49)f(49).\newlinef(x)=3+xf(x) = 3 + \sqrt{x}\newlinef(49)=f(49) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=3+xf(x) = 3 + \sqrt{x} and we need to find the value of f(49)f(49).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(49)f(49), we substitute 4949 for xx in the function:\newlinef(49)=3+49f(49) = 3 + \sqrt{49}
  3. Calculate Square Root: Calculate the square root of the input value.\newlineThe square root of 4949 is 77, so we have:\newlinef(49)=3+7f(49) = 3 + 7
  4. Add Numbers: Add the numbers to find the final value.\newlineAdding 33 and 77 gives us:\newlinef(49)=10f(49) = 10

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