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Use the following function rule to find f(49)f(49).\newlinef(x)=11+10xf(x) = 11 + 10\sqrt{x}\newlinef(49)=f(49) = _____

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Q. Use the following function rule to find f(49)f(49).\newlinef(x)=11+10xf(x) = 11 + 10\sqrt{x}\newlinef(49)=f(49) = _____
  1. Identify function rule and input: Identify the function rule and the input value.\newlineWe are given the function rule f(x)=11+10xf(x) = 11 + 10\sqrt{x} and we need to find the value of f(49)f(49).
  2. Substitute input into rule: Substitute the input value into the function rule.\newlineTo find f(49)f(49), we substitute xx with 4949 in the function rule.\newlinef(49)=11+1049f(49) = 11 + 10\sqrt{49}
  3. Calculate square root: Calculate the square root of the input value.\newlineThe square root of 4949 is 77, since 7×7=497 \times 7 = 49.\newlinef(49)=11+10×7f(49) = 11 + 10 \times 7
  4. Multiply square root by 1010: Multiply the square root result by 1010.\newlineNow we multiply 77 by 1010 to get 7070.\newlinef(49)=11+70f(49) = 11 + 70
  5. Add 1111 to result: Add 1111 to the result of the multiplication.\newlineFinally, we add 1111 to 7070 to get the value of f(49)f(49).\newlinef(49)=11+70=81f(49) = 11 + 70 = 81

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