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Use the following function rule to find f(49)f(49).\newlinef(x)=10x+4f(x) = 10\sqrt{x} + 4\newlinef(49)=f(49) = _____

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Full solution

Q. Use the following function rule to find f(49)f(49).\newlinef(x)=10x+4f(x) = 10\sqrt{x} + 4\newlinef(49)=f(49) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=10x+4f(x) = 10\sqrt{x} + 4 and we need to find the value of f(49)f(49).
  2. Substitute Input into Function: Substitute the input value into the function.\newlinef(49)=1049+4f(49) = 10\sqrt{49} + 4
  3. Calculate Square Root: Calculate the square root of the input value. 49=7\sqrt{49} = 7
  4. Multiply by Coefficient: Multiply the square root by the coefficient. 10×7=7010 \times 7 = 70
  5. Add Constant Term: Add the constant term to the product.\newlinef(49)=70+4f(49) = 70 + 4
  6. Simplify for Final Answer: Simplify the expression to find the final answer. f(49)=74f(49) = 74

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