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Use the following function rule to find f(36)f(36).\newlinef(x)=12+xf(x) = 12 + \sqrt{x}\newlinef(36)=f(36) = _____

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Q. Use the following function rule to find f(36)f(36).\newlinef(x)=12+xf(x) = 12 + \sqrt{x}\newlinef(36)=f(36) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=12+xf(x) = 12 + \sqrt{x} and we need to find the value of f(36)f(36).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(36)f(36), we substitute 3636 for xx in the function:\newlinef(36)=12+36f(36) = 12 + \sqrt{36}
  3. Calculate Square Root: Calculate the square root of the input value.\newlineThe square root of 3636 is 66, so we continue the calculation:\newlinef(36)=12+6f(36) = 12 + 6
  4. Add Numbers: Add the numbers to find the final value.\newlineNow we add 1212 and 66 to get the final value of f(36)f(36):\newlinef(36)=18f(36) = 18

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