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Use the following function rule to find f(16)f(16).\newlinef(x)=1+xf(x) = 1 + \sqrt{x}\newlinef(16)=f(16) = _____

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Q. Use the following function rule to find f(16)f(16).\newlinef(x)=1+xf(x) = 1 + \sqrt{x}\newlinef(16)=f(16) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=1+xf(x) = 1 + \sqrt{x} and we need to find the value of f(16)f(16).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(16)f(16), we substitute xx with 1616 in the function f(x)f(x).\newlinef(16)=1+16f(16) = 1 + \sqrt{16}
  3. Calculate Square Root: Calculate the square root of the input value.\newlineThe square root of 1616 is 44, since 4×4=164 \times 4 = 16.\newlinef(16)=1+4f(16) = 1 + 4
  4. Add to Get Final Result: Add the square root to 11 to get the final result.\newlinef(16)=1+4=5f(16) = 1 + 4 = 5

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