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Let’s check out your problem:
Use the following function rule to find
f
(
144
)
f(144)
f
(
144
)
.
\newline
f
(
x
)
=
5
x
+
7
f(x) = 5\sqrt{x} + 7
f
(
x
)
=
5
x
+
7
\newline
f
(
144
)
=
f(144) =
f
(
144
)
=
_____
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Math Problems
Algebra 2
Evaluate functions
Full solution
Q.
Use the following function rule to find
f
(
144
)
f(144)
f
(
144
)
.
\newline
f
(
x
)
=
5
x
+
7
f(x) = 5\sqrt{x} + 7
f
(
x
)
=
5
x
+
7
\newline
f
(
144
)
=
f(144) =
f
(
144
)
=
_____
Identify Function and Input:
Identify the function and the input value.
\newline
The function given is
f
(
x
)
=
5
x
+
7
f(x) = 5\sqrt{x} + 7
f
(
x
)
=
5
x
+
7
, and we need to find the value of
f
(
144
)
f(144)
f
(
144
)
.
Substitute Input into Function:
Substitute the input value into the function.
\newline
To find
f
(
144
)
f(144)
f
(
144
)
, we substitute
144
144
144
for
x
x
x
in the function:
\newline
f
(
144
)
=
5
144
+
7
f(144) = 5\sqrt{144} + 7
f
(
144
)
=
5
144
+
7
Calculate Square Root:
Calculate the
square root
of
144
144
144
.
\newline
The square root of
144
144
144
is
12
12
12
, since
12
×
12
=
144
12 \times 12 = 144
12
×
12
=
144
.
Multiply and Add:
Multiply the square root by
5
5
5
and add
7
7
7
. Now we multiply
5
5
5
by the square root of
144
144
144
we found in the previous step:
f
(
144
)
=
5
×
12
+
7
f(144) = 5 \times 12 + 7
f
(
144
)
=
5
×
12
+
7
Perform Arithmetic Operations:
Perform the arithmetic operations.
\newline
f
(
144
)
=
60
+
7
f(144) = 60 + 7
f
(
144
)
=
60
+
7
\newline
f
(
144
)
=
67
f(144) = 67
f
(
144
)
=
67
More problems from Evaluate functions
Question
What is the domain of this function?
\newline
(
9
,
–
2
)
(
6
,
–
10
)
(
–
3
,
9
)
(
5
,
2
)
(9,–2)(6,–10)(–3,9)(5,2)
(
9
,
–2
)
(
6
,
–10
)
(
–3
,
9
)
(
5
,
2
)
\newline
Choices:
\newline
(
A
)
{
–
3
,
5
,
6
,
9
}
(
B
)
{
–
10
,
–
2
,
2
,
9
}
(
C
)
{
2
,
5
,
6
,
9
}
(
D
)
{
–
6
,
–
3
,
5
,
9
}
(A)\{–3,5,6,9\}\newline(B)\{–10,–2,2,9\}\newline(C)\{2,5,6,9\}\newline(D)\{–6,–3,5,9\}
(
A
)
{
–3
,
5
,
6
,
9
}
(
B
)
{
–10
,
–2
,
2
,
9
}
(
C
)
{
2
,
5
,
6
,
9
}
(
D
)
{
–6
,
–3
,
5
,
9
}
Get tutor help
Posted 11 months ago
Question
Look at this set of ordered pairs:
\newline
(
2
,
14
)
(2, 14)
(
2
,
14
)
\newline
(
10
,
12
)
(10, 12)
(
10
,
12
)
\newline
(
3
,
−
19
)
(3, -19)
(
3
,
−
19
)
\newline
Is this relation a function?
\newline
Choices:
\newline
[[yes]
\text{[[yes]}
[[yes]
[no]]
\text{[no]]}
[no]]
Get tutor help
Posted 11 months ago
Question
Use the following function rule to find
f
(
11
)
f(11)
f
(
11
)
.
\newline
f
(
x
)
=
−
10
−
7
x
f(x) = -10 - 7x
f
(
x
)
=
−
10
−
7
x
\newline
f
(
11
)
=
f(11) =
f
(
11
)
=
_____
Get tutor help
Posted 11 months ago
Question
Find the slope of the line
y
=
−
3
x
−
2
5
y = -3x - \frac{2}{5}
y
=
−
3
x
−
5
2
.
\newline
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Posted 11 months ago
Question
A line has a slope of
3
3
3
and passes through the point
(
−
2
,
−
10
)
(-2,-10)
(
−
2
,
−
10
)
. Write its equation in slope-intercept form.
\newline
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Get tutor help
Posted 11 months ago
Question
What is the range of this function?
\newline
y = |x|
\newline
Choices:
\newline
all real numbers
\text{all real numbers}
all real numbers
\newline
{
y
∣
y
≥
0
}
\{y \mid y \geq 0\}
{
y
∣
y
≥
0
}
\newline
{
y
∣
y
≤
0
}
\{y \mid y \leq 0\}
{
y
∣
y
≤
0
}
\newline
{
y
∣
y
>
0
}
\{y \mid y > 0\}
{
y
∣
y
>
0
}
Get tutor help
Posted 1 year ago
Question
Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is the translation
1
1
1
unit down of
f
(
x
)
=
∣
x
∣
f(x) = |x|
f
(
x
)
=
∣
x
∣
.
\newline
Write your answer in the form
a
∣
x
−
h
∣
+
k
a|x - h| + k
a
∣
x
−
h
∣
+
k
, where
a
a
a
,
h
h
h
, and
k
k
k
are integers.
\newline
g
(
x
)
=
g(x) =
g
(
x
)
=
______
\newline
Get tutor help
Posted 1 year ago
Question
What is the domain of this function?
\newline
(
8
,
–
1
)
(
7
,
–
11
)
(
–
4
,
10
)
(
4
,
3
)
(8,–1)(7,–11)(–4,10)(4,3)
(
8
,
–1
)
(
7
,
–11
)
(
–4
,
10
)
(
4
,
3
)
\newline
Choices:
\newline
(
A
)
{
–
4
,
4
,
7
,
8
}
(A)\{–4,4,7,8\}\newline
(
A
)
{
–4
,
4
,
7
,
8
}
(
B
)
{
–
11
,
–
1
,
3
,
10
}
(B)\{–11,–1,3,10\}\newline
(
B
)
{
–11
,
–1
,
3
,
10
}
(
C
)
{
3
,
4
,
7
,
8
}
(C)\{3,4,7,8\}\newline
(
C
)
{
3
,
4
,
7
,
8
}
(
D
)
{
–
7
,
–
4
,
4
,
8
}
(D)\{–7,–4,4,8\}
(
D
)
{
–7
,
–4
,
4
,
8
}
Get tutor help
Posted 1 year ago
Question
What is the domain of this function?
\newline
(
10
,
–
3
)
(
2
,
–
9
)
(
–
5
,
8
)
(
3
,
1
)
(10,\,–3)(2,\,–9)(–5,\,8)(3,\,1)
(
10
,
–3
)
(
2
,
–9
)
(
–5
,
8
)
(
3
,
1
)
\newline
Choices:
\newline
[
{
–
5
,
2
,
3
,
10
}
]
[
{
–
9
,
–
3
,
1
,
8
}
]
[
{
1
,
2
,
3
,
10
}
]
[
{
–
10
,
–
5
,
2
,
3
}
]
[\{–5,2,3,10\}][\{–9,\,–3,1,8\}][\{1,2,3,10\}][\{–10,\,–5,2,3\}]
[{
–5
,
2
,
3
,
10
}]
[{
–9
,
–3
,
1
,
8
}]
[{
1
,
2
,
3
,
10
}]
[{
–10
,
–5
,
2
,
3
}]
Get tutor help
Posted 11 months ago
Question
What is the domain of this function?
\newline
(
1
,
–
4
)
(
9
,
–
12
)
(
–
6
,
11
)
(
7
,
5
)
(1,–4)(9,–12)(–6,11)(7,5)
(
1
,
–4
)
(
9
,
–12
)
(
–6
,
11
)
(
7
,
5
)
\newline
Choices:
(
A
)
{
–
6
,
1
,
7
,
9
}
\newline\\(A)\{–6,1,7,9\}\newline
(
A
)
{
–6
,
1
,
7
,
9
}
(
B
)
{
–
12
,
–
4
,
5
,
11
}
(B)\{–12,–4,5,11\}\newline
(
B
)
{
–12
,
–4
,
5
,
11
}
(
C
{
5
,
1
,
7
,
9
}
(C\{5,1,7,9\}\newline
(
C
{
5
,
1
,
7
,
9
}
(
D
)
{
–
9
,
–
6
,
1
,
7
}
(D)\{–9,–6,1,7\}
(
D
)
{
–9
,
–6
,
1
,
7
}
Get tutor help
Posted 11 months ago
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