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Use the following function rule to find f(121)f(121).\newlinef(x)=6+2xf(x) = 6 + 2\sqrt{x}\newlinef(121)=f(121) = _____

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Q. Use the following function rule to find f(121)f(121).\newlinef(x)=6+2xf(x) = 6 + 2\sqrt{x}\newlinef(121)=f(121) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=6+2xf(x) = 6 + 2\sqrt{x} and we need to find the value of f(121)f(121).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(121)f(121), we substitute 121121 for xx in the function:\newlinef(121)=6+2121f(121) = 6 + 2\sqrt{121}
  3. Calculate Square Root: Calculate the square root of 121121. The square root of 121121 is 1111, since 11×11=12111 \times 11 = 121.
  4. Continue Calculation with Result: Continue the calculation with the square root result.\newlineNow that we know 121=11\sqrt{121} = 11, we can continue the calculation:\newlinef(121)=6+2×11f(121) = 6 + 2 \times 11
  5. Multiply and Calculate: Multiply 22 by 1111. \newline2×112 \times 11 equals 2222. \newlinef(121)=6+22f(121) = 6 + 22
  6. Add for Final Result: Add 66 to 2222 to get the final result.\newline6+226 + 22 equals 2828.\newlinef(121)=28f(121) = 28

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