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Use the following function rule to find f(12)f(12).\newlinef(x)=1288+xf(x) = 12\sqrt{88 + x}\newlinef(12)=f(12) = _____

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Q. Use the following function rule to find f(12)f(12).\newlinef(x)=1288+xf(x) = 12\sqrt{88 + x}\newlinef(12)=f(12) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=1288+xf(x) = 12\sqrt{88 + x} and we need to find the value of f(12)f(12).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(12)f(12), we replace xx with 1212 in the function:\newlinef(12)=12(88+12)f(12) = 12\sqrt{(88 + 12)}
  3. Simplify Expression: Simplify the expression inside the square root.\newlineCalculate the sum inside the square root: 88+12=10088 + 12 = 100
  4. Substitute Simplified Value: Substitute the simplified value back into the function.\newlineNow we have:\newlinef(12)=12100f(12) = 12\sqrt{100}
  5. Calculate Square Root: Calculate the square root of 100100. The square root of 100100 is 1010: 100=10\sqrt{100} = 10
  6. Multiply by Coefficient: Multiply the square root by the coefficient.\newlineNow multiply the square root by 1212:\newlinef(12)=12×10f(12) = 12 \times 10
  7. Perform Final Multiplication: Perform the multiplication to find the final answer. f(12)=120f(12) = 120

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