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Let’s check out your problem:
Use the following function rule to find
f
(
−
2
)
f(-2)
f
(
−
2
)
.
\newline
f
(
x
)
=
10
+
6
x
f(x) = 10 + 6x
f
(
x
)
=
10
+
6
x
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Math Problems
Precalculus
Evaluate functions
Full solution
Q.
Use the following function rule to find
f
(
−
2
)
f(-2)
f
(
−
2
)
.
\newline
f
(
x
)
=
10
+
6
x
f(x) = 10 + 6x
f
(
x
)
=
10
+
6
x
Identify Function and Input:
Identify the function and the input value.
\newline
We are given the function
f
(
x
)
=
10
+
6
x
f(x) = 10 + 6x
f
(
x
)
=
10
+
6
x
and we need to find the value of
f
(
–
2
)
f(–2)
f
(
–2
)
.
Substitute Input into Function:
Substitute the input value into the function.
\newline
To find
f
(
-
2
)
f(\text{-}2)
f
(
-
2
)
, we replace
x
x
x
with
-
2
\text{-}2
-
2
in the function
f
(
x
)
f(x)
f
(
x
)
.
\newline
f
(
-
2
)
=
10
+
6
(
-
2
)
f(\text{-}2) = 10 + 6(\text{-}2)
f
(
-
2
)
=
10
+
6
(
-
2
)
Perform Multiplication:
Perform the multiplication.
\newline
Now we calculate
6
6
6
times
–
2
–2
–2
.
\newline
6
(
–
2
)
=
–
12
6(–2) = –12
6
(
–2
)
=
–12
Add to Constant Term:
Add the result to the constant term in the function.
\newline
We add the result from Step
3
3
3
to the constant term
10
10
10
.
\newline
f
(
–
2
)
=
10
+
(
–
12
)
f(–2) = 10 + (–12)
f
(
–2
)
=
10
+
(
–12
)
Simplify for Final Answer:
Simplify the expression to find the final answer.
\newline
f
(
−
2
)
=
10
−
12
f(-2) = 10 - 12
f
(
−
2
)
=
10
−
12
\newline
f
(
−
2
)
=
−
2
f(-2) = -2
f
(
−
2
)
=
−
2
More problems from Evaluate functions
Question
What is the domain of this function?
\newline
(
9
,
–
2
)
(
6
,
–
10
)
(
–
3
,
9
)
(
5
,
2
)
(9,–2)(6,–10)(–3,9)(5,2)
(
9
,
–2
)
(
6
,
–10
)
(
–3
,
9
)
(
5
,
2
)
\newline
Choices:
\newline
(
A
)
{
–
3
,
5
,
6
,
9
}
(
B
)
{
–
10
,
–
2
,
2
,
9
}
(
C
)
{
2
,
5
,
6
,
9
}
(
D
)
{
–
6
,
–
3
,
5
,
9
}
(A)\{–3,5,6,9\}\newline(B)\{–10,–2,2,9\}\newline(C)\{2,5,6,9\}\newline(D)\{–6,–3,5,9\}
(
A
)
{
–3
,
5
,
6
,
9
}
(
B
)
{
–10
,
–2
,
2
,
9
}
(
C
)
{
2
,
5
,
6
,
9
}
(
D
)
{
–6
,
–3
,
5
,
9
}
Get tutor help
Posted 10 months ago
Question
Look at this set of ordered pairs:
\newline
(
2
,
14
)
(2, 14)
(
2
,
14
)
\newline
(
10
,
12
)
(10, 12)
(
10
,
12
)
\newline
(
3
,
−
19
)
(3, -19)
(
3
,
−
19
)
\newline
Is this relation a function?
\newline
Choices:
\newline
[[yes]
\text{[[yes]}
[[yes]
[no]]
\text{[no]]}
[no]]
Get tutor help
Posted 10 months ago
Question
Use the following function rule to find
f
(
11
)
f(11)
f
(
11
)
.
\newline
f
(
x
)
=
−
10
−
7
x
f(x) = -10 - 7x
f
(
x
)
=
−
10
−
7
x
\newline
f
(
11
)
=
f(11) =
f
(
11
)
=
_____
Get tutor help
Posted 10 months ago
Question
Find the slope of the line
y
=
−
3
x
−
2
5
y = -3x - \frac{2}{5}
y
=
−
3
x
−
5
2
.
\newline
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
\newline
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Posted 10 months ago
Question
A line has a slope of
3
3
3
and passes through the point
(
−
2
,
−
10
)
(-2,-10)
(
−
2
,
−
10
)
. Write its equation in slope-intercept form.
\newline
Write your answer using integers, proper fractions, and improper fractions in simplest form.
Get tutor help
Posted 10 months ago
Question
What is the range of this function?
\newline
y = |x|
\newline
Choices:
\newline
all real numbers
\text{all real numbers}
all real numbers
\newline
{
y
∣
y
≥
0
}
\{y \mid y \geq 0\}
{
y
∣
y
≥
0
}
\newline
{
y
∣
y
≤
0
}
\{y \mid y \leq 0\}
{
y
∣
y
≤
0
}
\newline
{
y
∣
y
>
0
}
\{y \mid y > 0\}
{
y
∣
y
>
0
}
Get tutor help
Posted 1 year ago
Question
Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is the translation
1
1
1
unit down of
f
(
x
)
=
∣
x
∣
f(x) = |x|
f
(
x
)
=
∣
x
∣
.
\newline
Write your answer in the form
a
∣
x
−
h
∣
+
k
a|x - h| + k
a
∣
x
−
h
∣
+
k
, where
a
a
a
,
h
h
h
, and
k
k
k
are integers.
\newline
g
(
x
)
=
g(x) =
g
(
x
)
=
______
\newline
Get tutor help
Posted 1 year ago
Question
What is the domain of this function?
\newline
(
8
,
–
1
)
(
7
,
–
11
)
(
–
4
,
10
)
(
4
,
3
)
(8,–1)(7,–11)(–4,10)(4,3)
(
8
,
–1
)
(
7
,
–11
)
(
–4
,
10
)
(
4
,
3
)
\newline
Choices:
\newline
(
A
)
{
–
4
,
4
,
7
,
8
}
(A)\{–4,4,7,8\}\newline
(
A
)
{
–4
,
4
,
7
,
8
}
(
B
)
{
–
11
,
–
1
,
3
,
10
}
(B)\{–11,–1,3,10\}\newline
(
B
)
{
–11
,
–1
,
3
,
10
}
(
C
)
{
3
,
4
,
7
,
8
}
(C)\{3,4,7,8\}\newline
(
C
)
{
3
,
4
,
7
,
8
}
(
D
)
{
–
7
,
–
4
,
4
,
8
}
(D)\{–7,–4,4,8\}
(
D
)
{
–7
,
–4
,
4
,
8
}
Get tutor help
Posted 1 year ago
Question
What is the domain of this function?
\newline
(
10
,
–
3
)
(
2
,
–
9
)
(
–
5
,
8
)
(
3
,
1
)
(10,\,–3)(2,\,–9)(–5,\,8)(3,\,1)
(
10
,
–3
)
(
2
,
–9
)
(
–5
,
8
)
(
3
,
1
)
\newline
Choices:
\newline
[
{
–
5
,
2
,
3
,
10
}
]
[
{
–
9
,
–
3
,
1
,
8
}
]
[
{
1
,
2
,
3
,
10
}
]
[
{
–
10
,
–
5
,
2
,
3
}
]
[\{–5,2,3,10\}][\{–9,\,–3,1,8\}][\{1,2,3,10\}][\{–10,\,–5,2,3\}]
[{
–5
,
2
,
3
,
10
}]
[{
–9
,
–3
,
1
,
8
}]
[{
1
,
2
,
3
,
10
}]
[{
–10
,
–5
,
2
,
3
}]
Get tutor help
Posted 10 months ago
Question
What is the domain of this function?
\newline
(
1
,
–
4
)
(
9
,
–
12
)
(
–
6
,
11
)
(
7
,
5
)
(1,–4)(9,–12)(–6,11)(7,5)
(
1
,
–4
)
(
9
,
–12
)
(
–6
,
11
)
(
7
,
5
)
\newline
Choices:
(
A
)
{
–
6
,
1
,
7
,
9
}
\newline\\(A)\{–6,1,7,9\}\newline
(
A
)
{
–6
,
1
,
7
,
9
}
(
B
)
{
–
12
,
–
4
,
5
,
11
}
(B)\{–12,–4,5,11\}\newline
(
B
)
{
–12
,
–4
,
5
,
11
}
(
C
{
5
,
1
,
7
,
9
}
(C\{5,1,7,9\}\newline
(
C
{
5
,
1
,
7
,
9
}
(
D
)
{
–
9
,
–
6
,
1
,
7
}
(D)\{–9,–6,1,7\}
(
D
)
{
–9
,
–6
,
1
,
7
}
Get tutor help
Posted 10 months ago
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